In the given reaction `C_6H_5-underset(O)underset(||)C-CH_3overset(NH_2OH//H^(o+))rarr[X]overset(Na//C_2H_5OH)rarr[Y]`
[Y] will be

Options

A. `C_6H_5-underset(CH_3)underset(|)(CH)-NH_2`
B. `C_6H_5-underset(CH_3)underset(|)(CH)-NH-CH_3`
C. `C_6H_5-overset(O)overset(||)C-NH-CH_3`
D. `CH_3-overset(O)overset(||)C-NH-C_6H_5`

Answer

To solve the problem step by step, we will analyze the given reaction involving the compound C6H5COCH3 (benzophenone) and determine the final product Y after the specified reactions.

### Step 1: Identify the Starting Compound
The starting compound is C6H5COCH3, which is known as acetophenone.

### Step 2: Reaction with NH2OH and H+
When acetophenone (C6H5COCH3) reacts with hydroxylamine (NH2OH) in the presence of an acid (H+), it undergoes a condensation reaction. In this reaction, a water molecule is eliminated, resulting in the formation of an oxime.

**Reaction:**
\[ \text{C6H5COCH3} + \text{NH2OH} \xrightarrow{H^+} \text{C6H5C(=NOH)CH3} + H2O \]

The product formed is C6H5C(=NOH)CH3, which is called an oxime. We will denote this compound as [X].

### Step 3: Reaction of [X] with Sodium in Ethanol
The next step involves treating the oxime [X] with sodium (Na) in ethanol (C2H5OH). This reaction is known as the reduction of the oxime to form an amine.

**Reaction:**
\[ \text{C6H5C(=NOH)CH3} + \text{Na} \xrightarrow{C2H5OH} \text{C6H5CH(CH3)NH2} \]

In this reaction, the oxime is reduced to form an amine. The resulting product is C6H5CH(CH3)NH2, which is an amine.

### Step 4: Identify the Final Product [Y]
The final product [Y] is C6H5CH(CH3)NH2. This compound can also be referred to as N-methylbenzamine.

### Final Answer
Thus, the compound [Y] formed in the reaction is:
\[ \text{C6H5CH(CH3)NH2} \]

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