Home
Class 12
CHEMISTRY
An element with atomic mass 100 has a bc...

An element with atomic mass 100 has a bcc structure and edge length 400 pm. The density of element is

A

`10.376g//cm^3`

B

`5.188g//cm^3`

C

`7.289g//cm^3`

D

`2.144g//cm^3`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

An element (atomic mass = 100 g//mol ) having bcc structure has unit cell edge 400 pm .Them density of the element is

An element (atomic mass = 100 g//mol ) having bcc structure has unit cell edge 400 pm .Them density of the element is

An element (At. Mass =50 g/mol) having fcc structure has unit cell edge length 400 pm. The density of element is

An element crystallizes in f.c.c. lattice with edge length of 400 pm. The density of the element is 7 g cm^(-3) . How many atoms are present in 280 g of the element ?

An element has a bcc structure with a cell edge of 288 pm. The density of the element is 7.2 g cm^(-3) . How many atoms are present in 208 g of the element?

An element has a bcc structure with a cell edge of 288 pm. The density of the element is 7.2 g cm^(-3) . How many atoms are present in 208 g of the element?

An element has a bcc structure with a celledge of 288 pm. The density of the element is 7.2 g cm^(-3) . How many atins are present in 208 g of the element?

An element 'X' crystallises as face centred cubic lattice with edge length of 460 pm. The density of the element X, when molar mass of X atom is 60 g mol^(-1) is

An element A (Atomic weight =100 ) having b.c.c. structure has unit cell edge length 400 pm. Calculate the density of A, number of unit cells and number of atoms in 10 g of A.

An element of atomic mass 52 occurs in bcc structure with cell edge length of 288 pm. Calculate the Avodadro's number if density is 7.2gm//cm^(3) .