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The products of the reaction will be C...

The products of the reaction will be
`C_6H_6+CH_3-CH_2-CH_2-Broverset("Anhy.AlBr"_3)rarr`

A

`C_6H_5-CH_2-CH_2-CH_3`

B

C

as major product and `C_6H_5-CH_2-CH_2-CH_3` as minor product.

D

1 : 1 mixture of `C_6H_5-CH_2-CH_2-CH_3` and

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given problem, we will analyze the reaction between benzene and n-propyl bromide in the presence of anhydrous aluminum bromide (AlBr₃). This reaction is a Friedel-Crafts alkylation, which involves the formation of a carbocation that can react with benzene. ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants are benzene (C₆H₆) and n-propyl bromide (C₃H₇Br). 2. **Understand the Role of Aluminum Bromide**: - Anhydrous aluminum bromide (AlBr₃) acts as a Lewis acid and helps in generating a more reactive species from n-propyl bromide. 3. **Formation of Carbocation**: - When n-propyl bromide reacts with AlBr₃, it forms a carbocation. The reaction can be represented as: \[ \text{C}_3\text{H}_7\text{Br} + \text{AlBr}_3 \rightarrow \text{C}_3\text{H}_7^+ + \text{AlBr}_4^- \] - The n-propyl carbocation (C₃H₇⁺) is a primary carbocation. 4. **Carbocation Rearrangement**: - Primary carbocations can rearrange to form more stable secondary carbocations. In this case, the n-propyl carbocation can undergo a hydride shift to become a more stable isopropyl carbocation: \[ \text{C}_3\text{H}_7^+ \rightarrow \text{C}_3\text{H}_7^+ \text{ (isopropyl)} \] 5. **Electrophilic Attack on Benzene**: - The more stable isopropyl carbocation can then react with benzene. The electrophilic aromatic substitution occurs, leading to the formation of isopropylbenzene (also known as cumene): \[ \text{C}_6\text{H}_6 + \text{C}_3\text{H}_7^+ \rightarrow \text{C}_6\text{H}_5\text{C}(CH_3)_2 \] 6. **Minor Product Formation**: - Although the major product is isopropylbenzene, some n-propylbenzene will also be formed from the original n-propyl carbocation without rearrangement: \[ \text{C}_6\text{H}_6 + \text{C}_3\text{H}_7^+ \rightarrow \text{C}_6\text{H}_5\text{C}_3\text{H}_7 \] 7. **Final Products**: - The final products of the reaction are: - Major Product: Isopropylbenzene (C₆H₅C(CH₃)₂) - Minor Product: n-Propylbenzene (C₆H₅C₃H₇) ### Conclusion: The products of the reaction are isopropylbenzene (major product) and n-propylbenzene (minor product).
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