Home
Class 12
CHEMISTRY
When sulphur in the form of S(8) is heat...

When sulphur in the form of `S_(8)` is heated at 900K the initial pressure of 1 atm falls by `29%` at equilibrium. This is because of conversion of some `S_(8)` to `S_(2)`. Find the value of equilibrium constant for this reaction.

A

`2.55" atm"^3`

B

`255" atm"^3`

C

`25.5" atm"^3`

D

None

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

When sulphur in the form of S_(8) is heated at 900 K , the initial pressure of 1 atm falls by 10% at equilibrium. This is because of conversion of some S_(8) to S_(2) . Find the value of equilibrium constant for this reaction.

When S in the form of S_(8) is heated at 900 K , the initial pressure of 1 atmosphere falls by 29% at equilibrium. This is because of conversion of some S_(8) to S_(2) . Find the K_(p) for reaction.

When sulphur is heated at 800 K, the initial pressure of 1 atm decreases by 20% at equilibrium K_(p) of the reaction S_(8)(g)rArr4S_(2)(g) is :-

When sulphur ( in the form of S_(8) is heated at temperature T , at equilibrium , the pressure of S_(8) falls by 30% from 1.0 atm , because S_(8)(g) in partially converted into S_(2)(g) . Find the value of K_(P) for this reaction.

When sulphur ( in the form of S_(B)) is heated at temperature T , at equilibrium , the pressure of S_(B) falls by 30% from 1.0 atm , because S_(B)(g) in partially converted into S_(2)(g) . Find the value of K_(P) for this reaction.

For the reaction AB_(2)(g) rarr AB(g) + B(g) , the initial pressure of AB_(2)(g) was 6 atm and at equilibrium, total pressure was found to be 8 atm at 300 K. The equilibrium constant of the reaction at 300 K is……

When sulphur is heated at 900 K, S_(8) is converted to S_(2) . What will be the equilibrim constant for the reaction if initial pressure of 1 atm falls by 25% at equilibrium ?

The equilibrium constant for the reaction H_(2)+Br_(2)hArr2HBr is 67.8 at 300 K . The equilibrium constant for the dissociation of HBr is:

Write the unit of equilibrium constant (K_c) for the given reaction. BaCO_3(s) hArr BaO(s) +CO_2(g)

for the reaction P+Q rArr R + 2S , initially the concentration of P is equal to that of Q (1 molar) but at equilibrium the concentration of R will be twice of that of P, then the equilibrium constant of the reaction is