Silver cyanide `overset(Delta)rarr"Silver"+Aoverset(OH^-)rarrX+Y+H_2O` In the above sequence of reaction A,X,Y are respectively.

Options

A. `Cbar(N),(CN)_2,HCN`
B. `(CN)_2,CbarN,OCbarN`
C. `(CN)_2,N_2OCN`
D. `(CN)_2,C_2^(2-),NO_2^-`

Answer

To solve the question, we need to analyze the sequence of reactions involving silver cyanide (AgCN) and identify the compounds A, X, and Y.

### Step-by-Step Solution:

1. **Identify the Reaction of Silver Cyanide on Heating**:
- When silver cyanide (AgCN) is heated, it decomposes into silver (Ag) and another compound. The decomposition reaction can be represented as:
\[ 2 \text{AgCN} \xrightarrow{\Delta} 2 \text{Ag} + \text{C}_2\text{N}_2 \]
- Here, the compound formed is dicyan (C₂N₂), which is represented as A.

2. **Treatment of Compound A with Hydroxide Ion (OH⁻)**:
- The next step involves treating compound A (C₂N₂) with hydroxide ions (OH⁻). The reaction can be represented as:
\[ \text{C}_2\text{N}_2 + \text{OH}^- \rightarrow \text{CN}^- + \text{OCN}^- + \text{H}_2\text{O} \]
- In this reaction, the products formed are cyanide ion (CN⁻) and isocyanate ion (OCN⁻).

3. **Identify the Compounds**:
- From the above reactions, we can summarize:
- A (the compound formed after heating AgCN) is **C₂N₂**.
- X (the cyanide ion produced) is **CN⁻**.
- Y (the isocyanate ion produced) is **OCN⁻**.

### Final Answer:
- A = C₂N₂
- X = CN⁻
- Y = OCN⁻