Number of structural isomers of `C_4H_(10)O` that are ethers are

Options

A. 1
B. 2
C. 3
D. 4

Answer

To determine the number of structural isomers of C₄H₁₀O that are ethers, we can follow these steps:

### Step 1: Understand the molecular formula
The molecular formula C₄H₁₀O indicates that we have 4 carbon atoms, 10 hydrogen atoms, and 1 oxygen atom. Ethers have the general structure R-O-R', where R and R' are alkyl groups.

### Step 2: Identify possible alkyl groups
For C₄H₁₀O, we can have various combinations of alkyl groups. The possible alkyl groups that can be formed with 4 carbon atoms are:
- Butyl (C₄H₉)
- Propyl (C₃H₇) + Methyl (C₁H₃)
- Ethyl (C₂H₅) + Ethyl (C₂H₅)

### Step 3: Draw the structural isomers
Now, we can draw the structural isomers of ethers:
1. **Butyl methyl ether**: CH₃-O-CH₂-CH₂-CH₃ (also known as butyl ether)
2. **Isobutyl methyl ether**: CH₃-O-CH(CH₃)-CH₃
3. **Ethyl ethyl ether**: CH₃-CH₂-O-CH₂-CH₃

### Step 4: Count the isomers
From the structures drawn, we see that there are three distinct ethers:
1. CH₃-O-CH₂-CH₂-CH₃ (Butyl methyl ether)
2. CH₃-O-CH(CH₃)-CH₃ (Isobutyl methyl ether)
3. CH₃-CH₂-O-CH₂-CH₃ (Ethyl ethyl ether)

### Conclusion
Thus, the total number of structural isomers of C₄H₁₀O that are ethers is **3**.