Arrange the following metals in the increasing order of their densities. K,Sc, Ti and Ca

Options

A. `K lt Ca lt Sc lt Ti`
B. `Ti lt Sc lt Ca lt K`
C. `Sc lt Ti lt K lt Ca`
D. `Sc lt Ti lt Ca lt K`

Answer

To arrange the metals K (Potassium), Sc (Scandium), Ti (Titanium), and Ca (Calcium) in increasing order of their densities, we can follow these steps:

### Step 1: Identify the elements and their positions in the periodic table
- Potassium (K) is in Group 1 (alkali metals).
- Calcium (Ca) is in Group 2 (alkaline earth metals).
- Scandium (Sc) is in Group 3 (transition metals).
- Titanium (Ti) is in Group 4 (transition metals).

### Step 2: Understand the concept of density
Density is defined as mass per unit volume (Density = Mass/Volume). As we move across a period in the periodic table from left to right, the atomic size generally decreases while the atomic mass increases. This trend affects the density of the elements.

### Step 3: Arrange the elements based on their atomic size and mass
- Potassium (K) has a relatively low density due to its larger atomic size and lower mass compared to the others.
- Calcium (Ca) has a higher density than potassium but is still lower than scandium and titanium.
- Scandium (Sc) has a higher density than both potassium and calcium.
- Titanium (Ti) has the highest density among these metals.

### Step 4: List the densities of the metals (approximate values)
- Density of K: ~0.86 g/cm³
- Density of Ca: ~1.55 g/cm³
- Density of Sc: ~2.99 g/cm³
- Density of Ti: ~4.51 g/cm³

### Step 5: Arrange the metals in increasing order of density
Based on the densities listed:
1. Potassium (K) - 0.86 g/cm³
2. Calcium (Ca) - 1.55 g/cm³
3. Scandium (Sc) - 2.99 g/cm³
4. Titanium (Ti) - 4.51 g/cm³

### Final Answer
The increasing order of densities is:
**K < Ca < Sc < Ti**

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