`CH_3-C-=Noverset(H_2"O"//Delta)rarr(A)overset(H_2"O"//H^+)rarr(B)(A) and (B)` respectively are

Options

A. `CH_3-overset(O)overset(||)C-NH_2and CH_3COOH`
B. `CH_3COONH_4and CH_3COOH`
C. `CH_3CONH_2 and CH_3COONH_4`
D. `CH_3-CH=NH and CH_3COOH`

Answer

To solve the given question, we will analyze the reaction sequence step by step.

### Step 1: Identify the starting compound
The starting compound is given as CH₃C≡N (methyl cyanide or acetonitrile).

### Step 2: Understand the first reaction
The first reaction involves the partial hydrolysis of CH₃C≡N. Hydrolysis typically involves the addition of water (H₂O) to break chemical bonds. In this case, the triple bond between carbon and nitrogen is being hydrolyzed.

### Step 3: Determine the product A
Upon partial hydrolysis of CH₃C≡N, the product formed is an amide. The reaction can be represented as:
\[ \text{CH}_3C≡N + H_2O \xrightarrow{\Delta} \text{CH}_3C(=O)NH_2 \]
Thus, product A is:
\[ \text{A} = \text{CH}_3C(=O)NH_2 \]
This compound is known as acetamide.

### Step 4: Understand the second reaction
The second step involves the further hydrolysis of product A (acetamide) in the presence of an acid (H⁺). This reaction converts the amide into a carboxylic acid.

### Step 5: Determine the product B
The hydrolysis of acetamide (CH₃C(=O)NH₂) leads to the formation of acetic acid (ethanoic acid) and ammonia (NH₃). The reaction can be represented as:
\[ \text{CH}_3C(=O)NH_2 + H_2O \xrightarrow{H^+} \text{CH}_3COOH + NH_3 \]
Thus, product B is:
\[ \text{B} = \text{CH}_3COOH \]
This compound is known as acetic acid.

### Final Answer
- Product A: **CH₃C(=O)NH₂** (Acetamide)
- Product B: **CH₃COOH** (Acetic Acid)

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