For `0.1M` solution ,the colligative property will follow the order

Options

A. `NaCl gt Na_2SO_4 gt Na_3PO_4`
B. `NaCl lt Na_2SO_4 lt Na_3PO_4`
C. `NaCl gt Na_2SO_4 ~~ Na_3PO_4`
D. `NaCl lt Na_2SO_4 = Na_3PO_4`

Answer

To solve the question regarding the order of colligative properties for a `0.1M` solution, we need to analyze the dissociation of each solute into its constituent particles. Colligative properties depend on the number of solute particles in a solution, not on their identity.

### Step-by-Step Solution:

1. **Understanding Colligative Properties**:
- Colligative properties depend on the number of solute particles in a solution. The more particles present, the greater the effect on properties such as boiling point elevation, freezing point depression, vapor pressure lowering, and osmotic pressure.

2. **Identifying the Solutes**:
- We need to consider the solutes given in the options, which are likely to be ionic compounds that dissociate in solution.

3. **Dissociation of NaCl**:
- NaCl dissociates into 2 ions: Na⁺ and Cl⁻.
- Number of particles = 2.

4. **Dissociation of Na2SO4**:
- Na2SO4 dissociates into 3 ions: 2 Na⁺ and SO₄²⁻.
- Number of particles = 3.

5. **Dissociation of Na3PO4**:
- Na3PO4 dissociates into 4 ions: 3 Na⁺ and PO₄³⁻.
- Number of particles = 4.

6. **Ordering the Solutes by Number of Particles**:
- Now we can order the solutes based on the number of particles they produce in solution:
- Na3PO4 (4 particles)
- Na2SO4 (3 particles)
- NaCl (2 particles)

7. **Conclusion**:
- In decreasing order of the number of particles (and thus the effect on colligative properties), we have:
- Na3PO4 > Na2SO4 > NaCl
- In increasing order, it would be:
- NaCl < Na2SO4 < Na3PO4

8. **Selecting the Correct Option**:
- Based on the analysis, if the options provided are in increasing order of the number of particles, the correct answer would be:
- NaCl < Na2SO4 < Na3PO4 (Option B).