`BeO+CrarrCO+Xoverset(H_2O)rarrBe(OH)_2+Y`; X and Y in the above sequence are respectively

Options

A. `Be_2C and C_2H_2`
B. `Be_2C and CO_2`
C. `Be_2C and CH_4`
D. `Be_2C and C_2H_6`

Answer

To solve the problem step by step, we need to analyze the given chemical reaction:

1. **Identify the Reactants and Products**:
The reaction starts with beryllium oxide (BeO) and carbon (C). The products of the first reaction are carbon monoxide (CO) and an unknown compound (X). The next step involves treating the product with water (H2O) to yield beryllium hydroxide (Be(OH)₂) and another unknown compound (Y).

2. **First Reaction**:
The first reaction can be written as:
\[ \text{BeO} + \text{C} \rightarrow \text{CO} + X \]
To determine what X is, we need to consider the reaction of beryllium oxide with carbon. In this reaction, beryllium carbide (Be₂C) is formed as a product along with carbon monoxide.

3. **Identify X**:
From the first reaction, we conclude that:
\[ X = \text{Be}_2\text{C} \]

4. **Second Reaction**:
Now we treat the product (Be₂C) with water:
\[ \text{Be}_2\text{C} + \text{H}_2\text{O} \rightarrow \text{Be(OH)}_2 + Y \]
When beryllium carbide reacts with water, it produces beryllium hydroxide and methane (CH₄).

5. **Identify Y**:
From the second reaction, we conclude that:
\[ Y = \text{CH}_4 \]

6. **Final Answer**:
Therefore, the values of X and Y are:
\[ X = \text{Be}_2\text{C}, \quad Y = \text{CH}_4 \]

### Summary:
- X is beryllium carbide (Be₂C).
- Y is methane (CH₄).

### Final Answer:
X and Y in the above sequence are respectively Be₂C and CH₄.