The reaction of solid `XeF_(2)` with `AsF_(5)` in `1:1` ratio affords

Options

A. `XeF_(4) and AsF_(3)`
B. `XeF_(6) and AsF_(3)`
C. `[XeF]^(+)[AsF_(6)]^(-)`
D. `[Xe_(2)F_(3)]^(+)[AsF_(6)]^(-)`

Answer

To solve the question regarding the reaction of solid XeF₂ with AsF₅ in a 1:1 ratio, we can break down the process step by step.

### Step 1: Understand the Reactants
- We have two reactants: solid xenon difluoride (XeF₂) and arsenic pentafluoride (AsF₅).
- The ratio of the reactants is 1:1, meaning we will take one mole of XeF₂ and one mole of AsF₅ for the reaction.

### Step 2: Write the Reaction
- The reaction can be represented as:
\[ \text{XeF}_2 + \text{AsF}_5 \rightarrow \text{Products} \]

### Step 3: Identify the Products
- When XeF₂ reacts with AsF₅, they form a complex product. In this case, the reaction leads to the formation of:
\[ \text{XeF}^+ + \text{AsF}_6^- \]
- This indicates that the reaction produces a cation (XeF⁺) and an anion (AsF₆⁻).

### Step 4: Conclusion
- Therefore, the primary product formed from the reaction of solid XeF₂ with AsF₅ in a 1:1 ratio is:
\[ \text{XeF}^+ + \text{AsF}_6^- \]

### Final Answer
- The correct answer is option C: \(\text{XeF}^+ + \text{AsF}_6^-\).

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