When dilute `H_(2)SO_(4) and H_(2)O_(2)` are added to a solution of chromate ions, an intense blue colour is produced, which is stable in ether. Theis is due to the formation of

Options

A. `Cr_(2)O_(7)^(2-)`
B. `Cr_(2)O_(3)`
C. `CrO_(5)`
D. `CrO_(3)`

Answer

To solve the question regarding the intense blue color produced when dilute \( H_2SO_4 \) and \( H_2O_2 \) are added to a solution of chromate ions, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are chromate ions (\( CrO_4^{2-} \)), dilute sulfuric acid (\( H_2SO_4 \)), and hydrogen peroxide (\( H_2O_2 \)).

2. **Understand the Reaction**:
- When chromate ions are treated with dilute \( H_2SO_4 \), the \( H^+ \) ions from the acid can interact with the chromate ions.
- The presence of \( H_2O_2 \) introduces an oxidizing agent that can further react with the chromate ions.

3. **Write the Chemical Equation**:
- The reaction can be represented as follows:
\[ CrO_4^{2-} + 2 H^+ + 2 H_2O_2 \rightarrow CrO_5 + 3 H_2O \]
- Here, \( CrO_5 \) is formed, which is a peroxo compound of chromium.

4. **Identify the Product**:
- The product \( CrO_5 \) is known to produce an intense blue color when formed in solution.

5. **Stability in Ether**:
- The intense blue color of \( CrO_5 \) is stable in ether, which is a non-polar solvent. This stability is important for the identification of the compound.

6. **Conclusion**:
- Therefore, the intense blue color observed in the solution is due to the formation of \( CrO_5 \).

### Final Answer:
The intense blue color produced is due to the formation of \( CrO_5 \).