`"Phenol "overset(Na_(2)Cr_(2)O_(7))underset(H_(2)SO_(4))rarrX` The ratio of the number of `sigma` to `pi` bonds in the products X is

Answer

To solve the problem, we need to determine the product of the reaction of phenol with acidified sodium dichromate and then count the number of sigma and pi bonds in that product.

### Step-by-Step Solution:

1. **Identify the Reactant**:
The reactant is phenol, which has the molecular formula C6H5OH.

2. **Determine the Product**:
When phenol is oxidized with acidified sodium dichromate (Na2Cr2O7 in H2SO4), it undergoes oxidation to form benzoquinone. The structure of benzoquinone can be represented as C6H4O2.

3. **Draw the Structure of Benzoquinone**:
The structure of benzoquinone consists of a six-membered carbon ring with two carbonyl (C=O) groups.

4. **Count the Sigma Bonds**:
- Each carbon-carbon single bond (C-C) in the ring contributes one sigma bond.
- Each carbon-hydrogen bond (C-H) contributes one sigma bond.
- Each carbon-oxygen single bond (C-O) contributes one sigma bond.
- In benzoquinone, there are 6 C-C bonds, 4 C-H bonds, and 2 C=O bonds (each C=O has one sigma bond).
- Total sigma bonds = 6 (C-C) + 4 (C-H) + 2 (C=O) = 12 sigma bonds.

5. **Count the Pi Bonds**:
- Each double bond contributes one pi bond. In benzoquinone, there are 2 C=O double bonds and 2 C=C double bonds in the ring.
- Total pi bonds = 2 (from C=O) + 2 (from C=C) = 4 pi bonds.

6. **Calculate the Ratio of Sigma to Pi Bonds**:
- The ratio of sigma bonds to pi bonds is given by the formula:
\[ \text{Ratio} = \frac{\text{Number of Sigma Bonds}}{\text{Number of Pi Bonds}} = \frac{12}{4} = 3 \]

### Final Answer:
The ratio of the number of sigma to pi bonds in the product X (benzoquinone) is **3**.