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In the carbylamine reaction, R-X convert...

In the carbylamine reaction, `R-X` converted `R-Y` via the intermediate `Z, R-X, R-Y and Z`, respectively are

A

`R-NH_(2), R-NC,"carbene"`

B

`R-NH_(2), R-NC," nitrene"`

C

`R-NC, R-NH_(2)," carbene"`

D

`R-OH, R-NC," nitrene"`

Text Solution

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The correct Answer is:
To solve the question regarding the carbylamine reaction, we need to identify the compounds involved in the reaction: the starting material (R-X), the product (R-Y), and the intermediate (Z). Here’s the step-by-step breakdown: ### Step 1: Identify R-X (Starting Material) In the carbylamine reaction, the starting material is a primary amine. This is because primary amines react with chloroform in the presence of a strong base (potassium hydroxide) to form isocyanides. **R-X = Primary Amine (R-NH2)** ### Step 2: Identify the Intermediate (Z) During the reaction, chloroform (CHCl3) reacts with potassium hydroxide to generate a reactive intermediate known as a carbene. This carbene is a dichlorocarbene (CCl2) which is electron-deficient and can react with the amine. **Z = Dichlorocarbene (CCl2)** ### Step 3: Identify R-Y (Product) The product of the carbylamine reaction is an isocyanide, which is formed after the reaction of the primary amine with the carbene intermediate. The isocyanide has the general structure R-N≡C. **R-Y = Isocyanide (R-N≡C)** ### Conclusion Now we can summarize the findings: - R-X (Starting Material) = Primary Amine (R-NH2) - Z (Intermediate) = Dichlorocarbene (CCl2) - R-Y (Product) = Isocyanide (R-N≡C) ### Final Answer: - R-X = Primary Amine (R-NH2) - Z = Dichlorocarbene (CCl2) - R-Y = Isocyanide (R-N≡C)
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