The enolic form of given compound contians
`CH_(3)-CH_(2)-overset(O)overset(||)C-CH_(3)`
`x, sigma` bonds, y `pi` bonds, z lone pairs. The sum value of `(x+y+z)` is

Answer

To solve the problem, we need to determine the enolic form of the given compound and then count the number of sigma bonds (x), pi bonds (y), and lone pairs (z) in that structure. Finally, we will calculate the sum of x, y, and z.

### Step 1: Identify the Keto Form
The given compound is `CH3-CH2-C(=O)-CH3`. This is the keto form of the compound.

### Step 2: Convert to Enolic Form
To convert the keto form to the enolic form, we need to perform the following steps:
- The hydrogen atom on the carbon adjacent to the carbonyl group (C=O) shifts to the oxygen atom, forming a hydroxyl group (-OH).
- The double bond between the carbonyl carbon and the adjacent carbon shifts to form a double bond between the carbon and the carbon that was previously bonded to the hydrogen.

The resulting enolic form will be:
```
CH3
|
CH3-CH2-C(OH)=CH2
```
This structure can also be represented as `CH3-CH2-C(=C(OH)-CH2)`.

### Step 3: Count Sigma Bonds (x)
Now, we will count the sigma bonds in the enolic form:
- The CH3 group has 3 C-H sigma bonds.
- The CH2 group has 2 C-H sigma bonds.
- The CH2 group connected to the carbon with the hydroxyl group has 2 C-H sigma bonds.
- The C-C bonds contribute 2 sigma bonds (C-CH2 and C-CH).
- The C-O bond contributes 1 sigma bond.

Counting these:
- CH3: 3 sigma bonds
- CH2 (first): 2 sigma bonds
- CH2 (second): 2 sigma bonds
- C-C: 2 sigma bonds
- C-O: 1 sigma bond

Total sigma bonds (x) = 3 + 2 + 2 + 2 + 1 = 10 sigma bonds.

### Step 4: Count Pi Bonds (y)
Next, we count the pi bonds:
- There is one double bond between the carbon and the carbon that is bonded to the hydroxyl group, which contributes 1 pi bond.

Total pi bonds (y) = 1.

### Step 5: Count Lone Pairs (z)
Now, we will count the lone pairs:
- The oxygen atom in the hydroxyl group (OH) has 6 valence electrons (2s² 2p⁴). In the enolic form, it forms one sigma bond with carbon and has one hydrogen attached, which means it has 4 remaining electrons.
- These 4 electrons can be grouped into 2 lone pairs.

Total lone pairs (z) = 2.

### Step 6: Calculate the Sum (x + y + z)
Now we can calculate the sum of x, y, and z:
- x = 10 (sigma bonds)
- y = 1 (pi bonds)
- z = 2 (lone pairs)

Sum = x + y + z = 10 + 1 + 2 = 13.

### Final Answer
The sum value of (x + y + z) is **13**.