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Select the Z - isomer from the following...

Select the Z - isomer from the following alkenes

A

B

C

D

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To solve the question of selecting the Z-isomer from the given alkenes, we need to follow these steps: ### Step 1: Understand E-Z Isomerism E-Z isomerism occurs in alkenes where there are two different groups attached to each carbon of the double bond. For E-Z nomenclature: - Z (from the German "zusammen") means that the higher priority groups are on the same side of the double bond. - E (from the German "entgegen") means that the higher priority groups are on opposite sides of the double bond. ### Step 2: Identify Groups Attached to the Double Bond For each alkene, identify the groups attached to each carbon of the double bond. Ensure that the groups are different to apply E-Z nomenclature. ### Step 3: Assign Priorities Using Cahn-Ingold-Prelog Rules Using the Cahn-Ingold-Prelog priority rules, assign priorities to the groups attached to each carbon of the double bond: - Compare the atomic numbers of the atoms directly attached to the double-bonded carbons. The group with the higher atomic number gets the higher priority. - If the first atoms are the same, move to the next atoms in the groups until a difference is found. ### Step 4: Determine the Configuration (Z or E) Once the priorities are assigned, check the positions of the groups: - If the higher priority groups are on the same side, it is a Z-isomer. - If the higher priority groups are on opposite sides, it is an E-isomer. ### Step 5: Analyze Each Given Alkene Now, we will analyze each option provided in the question to determine which one is the Z-isomer. 1. **Option A**: Groups are the same on one side → Not applicable for E-Z isomerism. 2. **Option B**: Higher priority groups are on opposite sides → This is an E-isomer. 3. **Option C**: Higher priority groups are on the same side → This is a Z-isomer. 4. **Option D**: Higher priority groups are on opposite sides → This is an E-isomer. ### Conclusion After analyzing all the options, the correct answer is **Option C**, which is the Z-isomer. ---
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