Total number of enol possible for the compound formed during given reaction will be (including stereoisomer):
`CH_(3)MgBr+CH_(3)CH_(2)-overset(O)overset(||)(C)-CI rarr`

Answer

To solve the problem, we need to determine the total number of enols that can be formed from the reaction of methyl magnesium bromide (CH₃MgBr) with propanoyl chloride (CH₃CH₂COCl).

### Step-by-Step Solution:

1. **Identify the Reaction**:
The reaction involves the addition of CH₃MgBr to CH₃CH₂COCl. This reaction will yield a ketone. The structure of propanoyl chloride is CH₃CH₂C(=O)Cl.

2. **Formation of the Ketone**:
When CH₃MgBr reacts with propanoyl chloride, it replaces the chlorine atom and forms a ketone:
\[ CH₃CH₂C(=O)Cl + CH₃MgBr \rightarrow CH₃CH₂C(=O)CH₃ + MgClBr \]
The resulting ketone is 3-pentanone (CH₃CH₂C(=O)CH₃).

3. **Identify Possible Enols**:
Enols are formed from ketones through a process called enolization, where a hydrogen atom is removed from the carbon adjacent to the carbonyl group, and a double bond is formed between that carbon and the carbonyl carbon.

4. **Determine the Structure of the Ketone**:
The structure of 3-pentanone is:
\[ CH₃-CH₂-C(=O)-CH₃ \]

5. **Enolization**:
- The enol form can be derived from the ketone by removing a hydrogen from the carbon adjacent to the carbonyl:
- If we remove a hydrogen from the CH₂ group, we get:
\[ CH₃-CH=CH(OH)-CH₃ \]
- If we remove a hydrogen from the CH₃ group, we get:
\[ CH₃-CH₂-C(OH)=CH₂ \]

6. **Identify Stereoisomers**:
- For the first enol (from CH₂), we can have two stereoisomers (E and Z forms) due to the presence of different groups attached to the double bond.
- For the second enol (from CH₃), there are no stereoisomers since both groups attached to the double bond are the same (two hydrogens).

7. **Count the Total Enols**:
- From the first enol, we have 2 stereoisomers (E and Z).
- From the second enol, we have 1 form (no stereoisomers).
- Thus, the total number of enols including stereoisomers is:
\[ 2 \text{ (from first enol)} + 1 \text{ (from second enol)} = 3 \]

### Final Answer:
The total number of enols possible for the compound formed during the given reaction, including stereoisomers, is **3**.