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2-Mehtylbut-1-ene reacts wth mercuric ac...

2-Mehtylbut-1-ene reacts wth mercuric acetate in presence of water to form a product, which on reduction with `NaBH_(4)` yield

A

2 - Methylbutane -2- ol

B

2 - Methylbutan -1- ol

C

3 - Methylbutan -2- ol

D

none of the above

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The correct Answer is:
To solve the problem step by step, we will analyze the reaction of 2-methylbut-1-ene with mercuric acetate in the presence of water, followed by reduction with sodium borohydride (NaBH4). ### Step 1: Identify the Reactants The reactant is 2-methylbut-1-ene, which has the following structure: - CH2=CH-C(CH3)(CH2)-CH3 ### Step 2: Oxymercuration Reaction When 2-methylbut-1-ene reacts with mercuric acetate (Hg(OAc)2) in the presence of water, it undergoes an oxymercuration reaction. This reaction follows Markovnikov's rule, meaning that the more substituted carbon will bond with the mercuric acetate, and the hydroxyl group (OH) will attach to the less substituted carbon. 1. The double bond opens up, and the mercuric acetate adds across the double bond. 2. The HgOAc group attaches to the more substituted carbon (the one with the most alkyl groups), while the OH group attaches to the less substituted carbon. ### Step 3: Determine the Product of Oxymercuration The product formed after the oxymercuration step will be: - CH3-CH(OAc)-CH2-CH3 (where OAc is the acetate group attached to the more substituted carbon). ### Step 4: Demercuration In the next step, the reaction undergoes demercuration, where the acetate group is replaced by a hydroxyl group (OH) through the addition of water. The final product after this step will be: - CH3-CH(OH)-CH2-CH3 ### Step 5: Reduction with NaBH4 Now, when this alcohol (the product of the oxymercuration and demercuration) is reduced with sodium borohydride (NaBH4), it will convert the carbonyl group (if present) into an alcohol. However, in this case, we have already formed an alcohol. The product after reduction will remain: - CH3-CH(OH)-CH2-CH3 ### Step 6: Naming the Product The final product can be named as 2-methylbutan-2-ol. ### Final Answer The product obtained after the reduction with NaBH4 is **2-methylbutan-2-ol**. ---
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