Home
Class 12
CHEMISTRY
On breaking a cubic solid (edge = 1 m) i...

On breaking a cubic solid (edge = 1 m) into fine cubic particles of edge `1mum`, surface area becomes `nxx100000`. The value of n is ?

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow the reasoning laid out in the video transcript. ### Step 1: Calculate the volume of the large cube The edge length of the large cube is given as 1 meter. The volume \( V \) of a cube is calculated using the formula: \[ V = \text{edge}^3 \] So, the volume of the large cube is: \[ V_{\text{large}} = 1^3 = 1 \, \text{m}^3 \] ### Step 2: Calculate the volume of the small cube The edge length of the small cube is given as \( 1 \, \mu m \) (micrometer), which is equal to \( 1 \times 10^{-6} \, m \). Thus, the volume of the small cube is: \[ V_{\text{small}} = (1 \times 10^{-6})^3 = 1 \times 10^{-18} \, \text{m}^3 \] ### Step 3: Determine the number of small cubes To find out how many small cubes can be made from the large cube, we divide the volume of the large cube by the volume of a small cube: \[ \text{Number of small cubes} = \frac{V_{\text{large}}}{V_{\text{small}}} = \frac{1 \, \text{m}^3}{1 \times 10^{-18} \, \text{m}^3} = 10^{18} \] ### Step 4: Calculate the surface area of one small cube The surface area \( A \) of a cube is given by the formula: \[ A = 6 \times \text{side}^2 \] For the small cube: \[ A_{\text{small}} = 6 \times (1 \times 10^{-6})^2 = 6 \times 1 \times 10^{-12} \, \text{m}^2 = 6 \times 10^{-12} \, \text{m}^2 \] ### Step 5: Calculate the total surface area of all small cubes The total surface area \( A_{\text{total}} \) of all the small cubes is the surface area of one small cube multiplied by the number of small cubes: \[ A_{\text{total}} = A_{\text{small}} \times \text{Number of small cubes} = 6 \times 10^{-12} \, \text{m}^2 \times 10^{18} = 6 \times 10^{6} \, \text{m}^2 \] ### Step 6: Express the total surface area in terms of \( n \) According to the problem, the total surface area is given as \( n \times 100000 \, \text{m}^2 \): \[ 6 \times 10^{6} = n \times 10^{5} \] ### Step 7: Solve for \( n \) To find \( n \), we rearrange the equation: \[ n = \frac{6 \times 10^{6}}{10^{5}} = 6 \times 10^{1} = 60 \] Thus, the value of \( n \) is \( 60 \). ### Final Answer The value of \( n \) is \( 60 \). ---
Promotional Banner

Similar Questions

Explore conceptually related problems

A cube of 2cm edge is cut off into 8 cubes of 1cm edge. What is teir total surface area?

Find the edge of a cube whose surface area is 432\ m^2

A solid cube has an edge length of 5. what is the ratio of the cube's surface area of its volume?

The volume of a cube is increasing at a rate of 7c m^3//s ec How fast is the surface area increasing when the length of an edge is 12cm?

Find the surface area of a cube whose edge is 11\ c m

The volume of a cube is increasing at the rate of 8 c m^3//s . How fast is the surface area increasing when the length of an edge is 12 cm?

Three element A,B,C crystallize into a cubic solid lattice.Atoms A occupy the corners B atoms the cube centres and atom C the edge .The formula of the compound is

Derive an expression for the density of a cubic crystal whose edge is 'a' pm and contains z atoms per unit cell. The atomic mass of substance may be taken as M.

The lengths of three unequal edges of a rectangular solids block are in GP . if the volume of the block is 216 cm^(3) and the total surface area is 252cm ^(2) then the length of the longest edge is

A crystalline solid of a pure substance has a face-centred cubic structure with a cell edge of 400 pm. If the density of the substance in the crystal is 8 g cm^(-3) , then the number of atoms present in 256g of the crystal is N xx 10^(24) . The value of N is