The `S_(N)2` reaction involves back - side attack and therefore results in a ''Walden Inversion.'' For which one of the substrates shown would you be able to demonstrate that such back - side attack with ''Walden Inversion'' has infact occurred?
The `S_(N)2` reaction involves back - side attack and therefore results in a ''Walden Inversion.'' For which one of the substrates shown would you be able to demonstrate that such back - side attack with ''Walden Inversion'' has infact occurred?
A
1 - bromopropane
B
2 - bromobutane
C
3 - bromopentane
D
Methyl bromide
Text Solution
AI Generated Solution
The correct Answer is:
To determine which substrate would demonstrate a Walden inversion during an SN2 reaction, we need to analyze the chirality of the substrates provided. The SN2 reaction involves a backside attack by the nucleophile, leading to an inversion of configuration at the chiral center. Here’s a step-by-step breakdown of how to identify the correct substrate:
### Step 1: Understand the SN2 Mechanism
- The SN2 (Substitution Nucleophilic Bimolecular) reaction is characterized by a single step where the nucleophile attacks the substrate from the opposite side of the leaving group.
- This backside attack results in a geometric inversion known as Walden inversion.
**Hint:** Remember that for a Walden inversion to occur, the carbon atom attached to the leaving group must be chiral.
### Step 2: Identify Chiral Centers
- A chiral center is a carbon atom that is bonded to four different substituents. Only chiral centers can exhibit Walden inversion.
- Examine each substrate to check if the carbon atom bonded to the halogen (in this case, bromine) is chiral.
**Hint:** Look for a carbon atom bonded to four different groups or atoms.
### Step 3: Analyze the Given Substrates
- **1-Bromopropane:** The carbon attached to bromine is bonded to two hydrogen atoms and two other groups (not chiral).
- **2-Bromobutane:** The carbon attached to bromine is bonded to an ethyl group, a methyl group, a hydrogen atom, and the bromine (chiral).
- **2-Bromopentane:** Similar to 2-bromobutane, but check if the carbon is still chiral.
- **Methyl Bromide:** The carbon attached to bromine is bonded to three hydrogen atoms (not chiral).
**Hint:** Identify which of the substrates has a chiral carbon atom.
### Step 4: Confirm the Presence of Walden Inversion
- For the substrate to demonstrate Walden inversion, it must undergo the SN2 reaction with a chiral center.
- In the case of 2-bromobutane, when the nucleophile attacks from the backside, it will lead to an inversion of configuration from R to S or vice versa.
**Hint:** Remember that only the substrate with a chiral center can show Walden inversion.
### Conclusion
Based on the analysis, **2-bromobutane** is the only substrate that can demonstrate a Walden inversion due to the presence of a chiral carbon atom.
### Final Answer
The substrate that would demonstrate backside attack with Walden inversion is **2-bromobutane**.
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SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walden inversion by SN^(2) mechanism. The presence of hetro group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will gives SN^(2) mechanism gt
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Nucleophilic aliphatic substitution reaction is mainly of two types: S_(N)1 and S_(N)2 . The S_(N)1 mechanism is a two step process. Reaction velocity of S_(N)1 reaction depends only on the concentration of the substrate. Since product formation takes place by the formation of carbocation, optically active substrate gives (+) and (-) forms of the product. In most of the cases the product usually consits of 5-20% inverted product and 80-95% racemised species. The more stable the carbocation, the greater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic the solvent, the greater is the proportion of inversion. Which one of the following compound will give S_(N)1 reaction predominantly?
Nucleophilic aliphatic substitution reaction is mainly of two types: S_(N)1 and S_(N)2 . The S_(N)1 mechanism is a two step process. Reaction velocity of S_(N)1 reaction depends only on the concentration of the substrate. Since product formation takes place by the formation of carbocation, optically active substrate gives (+) and (-) forms of the product. In most of the cases the product usually consits of 5-20% inverted product and 80-95% racemised species. The more stable the carbocation, the greater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic the solvent, the greater is the proportion of inversion. For the gives reaction, Which substrate will give maximum racemisation?
SN^(2) reaction is a bimolecular reaction which takes places by the formation of T.S. Veolcity of the reaction depends on the concentration of the substrate as well as the nucleophile. The reaction is favoureed by strong Nu^(o-) and in the presence of polar aprotic sovlent, optically active halides give. Walken inversion by SN^(2) mechanism. The presence of hero group (atom) at beta-C atom, unsaturation at beta-C and (-overset(O)overset(||)(C)-) group at alpha-C atomn favor SN^(2) mechanism. Allyl halides and benzyl halides give SN^(1) and SN^(2) reactions. Allyl halides alos give SN^(2) mechanism EDG at ortho- and para- postions in benzyl halides favors SN^(1) mechanism, wheras EWG favors SN^(2) mechanism. Which of the following will give Walden inversion ?
Optically pure (+)-2 -chlorooctane, [alpha] = +40^@ , reacts with aq. NaOH in acetone to give optically pure (-)-2 -octanol, [alpha] = -12.0^@ . With partically racemised chloro compound whose [alpha] = + 30^@ , the [alpha] of alcohal product is - 6.0^@ . Calculate : (a) The percentage optical purity of partially racemised chloro compound and alcohol. (b) The percentage of inversion and racemisation. (c) The percentage of front-side and back-side attacks. (d) What interference can be drawn from the data in part (a) of the above example, about the mode of 2^@ alky1 halide. ( e) Give the rate expression. In terms if the expression, decrease the experimental changes for encourage (i) SN^1 , (ii) SN^2 ,
Nucleophilic aliphatic substitution reaction is mainly of two types: S_(N)1 and S_(N)2 . The S_(N)1 mechanism is a two step process. Reaction velocity of S_(N)1 reaction depends only on the concentration of the substrate. Since product formation takes place by the formation of carbocation, optically active substrate gives (+) and (-) forms of the product. In most of the cases the product usually consits of 5-20% inverted product and 80-95% racemised species. The more stable the carbocation, the greater is the proportion of racemisation. In solvolysis reaction, the more nucleophilic the solvent, the greater is the proportion of inversion. Which of the following compounds will give S_(N)1 and S_(N)2 reactions with considerable rate? I. C_(6)H_(5)-CH_(2)-Br (II) CH_(2)=CH-CH_(2)-Br (III) CH_(3)-CH(Br)CH_(3) (IV) Select the correct answer from teh codes given below
The rate law expresison is given for a typical reaction, n_(1)A + n_(2) B rarrP as r = k[A]^(n)[B]^(n2) . The reaction completes only in one step and A and B are present in the solution. If the reaction occurs in more than one step, then the rate law is expressed by consdering the slowest step, i.e., for S_(N)l reaction r = k[RX] . If the eraction occurs in more than one step and the rates of the steps involved are comparable, then steady state approximation is conisdered, i.e., the rate of formation of intermediate is always equal to the rate of decompoistion of the intermediate. Conisder the reaction: [[I_(2) underset(k_(1))overset(k_(2))hArr2I("rapid equilibrium")],[H_(2)+2I overset(k_(3))rarr 2HI("slow")]] Which of the following expresison is correct?
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