Each of the compounmds `Pt(NH_(3))_(6)Cl_(4), Cr(NH_(3))_(6)Cl_(3) and K_(2)PtCl_(6)Co(NH_(3))_(4)Cl_(3)` were dissolved in water to make its 0.01 M solution. The correct order of their increasing conductivity in solution is

Options

A. `K_(2){T Cl_(6) lt Co(NH_(3))_(4).l_(3) lt Cr(NH_(3))_(6)Cl_(3) lt Pt (NH_(3))_(6)Cl_(4)`
B. `Cr(NH_(3))_(6)Clk_(3) lt Co(NH_(3))_(4).Cl_(3) lt K_(2)PtCl_(6) lt Pt (NH_(3))_(6)Cl_(4)`
C. `Co(NH_(3))_(4).Cl_(3)lt K_(2)PtCl_(6) lt Cr(NH_(3))_(6)Cl_(3) lt Pt (NH_(3))_(6)Cl_(4)`
D. `Pt(NH_(3))_(6)Cl_(4) lt Co(NH_(3))_(6).Cl_(3) lt Cr(NH_(3))_(6) Cl_(3)lt K_(2)PtCl_(6)`

Answer

To determine the correct order of increasing conductivity for the given compounds when dissolved in water, we need to analyze the number of ions produced by each compound in solution. Conductivity is directly related to the number of ions present; more ions result in higher conductivity.

### Step-by-Step Solution:

1. **Identify the Compounds:**
- Pt(NH₃)₆Cl₄
- Cr(NH₃)₆Cl₃
- K₂PtCl₆
- Co(NH₃)₄Cl₃

2. **Determine the Number of Ions Produced by Each Compound:**
- For **Pt(NH₃)₆Cl₄**:
- 1 Pt ion + 6 NH₃ (neutral, does not contribute to conductivity) + 4 Cl⁻ ions
- Total ions = 1 + 0 + 4 = **5 ions**

- For **Cr(NH₃)₆Cl₃**:
- 1 Cr ion + 6 NH₃ (neutral) + 3 Cl⁻ ions
- Total ions = 1 + 0 + 3 = **4 ions**

- For **K₂PtCl₆**:
- 2 K⁺ ions + 1 Pt ion + 6 Cl⁻ ions
- Total ions = 2 + 1 + 6 = **9 ions**

- For **Co(NH₃)₄Cl₃**:
- 1 Co ion + 4 NH₃ (neutral) + 3 Cl⁻ ions
- Total ions = 1 + 0 + 3 = **4 ions**

3. **List the Compounds with Their Total Ion Counts:**
- Pt(NH₃)₆Cl₄: 5 ions
- Cr(NH₃)₆Cl₃: 4 ions
- K₂PtCl₆: 9 ions
- Co(NH₃)₄Cl₃: 4 ions

4. **Rank the Compounds by Number of Ions:**
- Cr(NH₃)₆Cl₃: 4 ions (lowest conductivity)
- Co(NH₃)₄Cl₃: 4 ions (same as above, but will be considered next)
- Pt(NH₃)₆Cl₄: 5 ions
- K₂PtCl₆: 9 ions (highest conductivity)

5. **Final Order of Increasing Conductivity:**
- Cr(NH₃)₆Cl₃ < Co(NH₃)₄Cl₃ < Pt(NH₃)₆Cl₄ < K₂PtCl₆

### Conclusion:
The correct order of increasing conductivity in the solution is:
**Cr(NH₃)₆Cl₃ < Co(NH₃)₄Cl₃ < Pt(NH₃)₆Cl₄ < K₂PtCl₆**