In the reaction sequence
`C_(6)H_(5)CHO overset(NH_(2)OH//H^(o+))underset(Delta)rarr(X) overset(P_(2)O_(5)//Delta)rarr (Y) overset(H_(2)O,H^(+))rarr(Z)`
(X), (Y) and (Z) respectively be

Options

A. `C_(6)H_(5)CH=N-OH, C_(6)H_(5)CN, C_(6)H_(5)COOH`
B. `C_(6)H_(5)CH=NOH, C_(6)H_(5)CONH_(2),C_(6)H_(5)CONH_(2)`
C. `C_(6)H_(5)-CH=NOH, C_(6)H_(5)COOH, C_(6)H_(5)CONH_(2)`
D. `C_(6)H_(5)-CH=NOH, C_(6)H_(5)COOH, C_(6)H_(5)CN`

Answer

To solve the given reaction sequence, we will analyze each step carefully.

### Step 1: Reaction of Benzaldehyde with Hydroxylamine
The first step involves the reaction of benzaldehyde (C₆H₅CHO) with hydroxylamine (NH₂OH) under heating conditions.

**Reaction:**
\[ C_6H_5CHO + NH_2OH \xrightarrow{Heat} C_6H_5CH=NOH + H_2O \]

**Product (X):** The product formed here is an oxime, specifically benzaldehyde oxime (C₆H₅CH=NOH).

### Step 2: Dehydration with Phosphorus Pentoxide
The next step involves the dehydration of the oxime (X) using phosphorus pentoxide (P₂O₅), which is a strong dehydrating agent.

**Reaction:**
\[ C_6H_5CH=NOH \xrightarrow{P_2O_5, Heat} C_6H_5CN \]

**Product (Y):** The product formed here is benzyl cyanide (C₆H₅CN), which is a nitrile.

### Step 3: Acid Hydrolysis of Benzyl Cyanide
The final step involves the acid hydrolysis of benzyl cyanide (Y) in the presence of water and acid.

**Reaction:**
\[ C_6H_5CN + H_2O \xrightarrow{H^+} C_6H_5COOH + NH_3 \]

**Product (Z):** The product formed here is benzoic acid (C₆H₅COOH) and ammonia (NH₃).

### Summary of Products:
- **(X)**: Benzaldehyde oxime (C₆H₅CH=NOH)
- **(Y)**: Benzyl cyanide (C₆H₅CN)
- **(Z)**: Benzoic acid (C₆H₅COOH)

### Final Answer:
- (X) = Benzaldehyde oxime (C₆H₅CH=NOH)
- (Y) = Benzyl cyanide (C₆H₅CN)
- (Z) = Benzoic acid (C₆H₅COOH)

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