How many `-OH` groups are present in one molecules of sucrose?

Answer

To determine how many `-OH` groups are present in one molecule of sucrose, we can follow these steps:

### Step 1: Understand the Composition of Sucrose
Sucrose is a disaccharide composed of two monosaccharides: glucose and fructose.

### Step 2: Draw the Structure of Sucrose
To visualize the `-OH` groups, we can draw the structural formula of sucrose.

- Glucose has the formula C₆H₁₂O₆ and contains several `-OH` groups.
- Fructose also has the formula C₆H₁₂O₆ and contains `-OH` groups as well.

### Step 3: Identify the `-OH` Groups in Glucose
In the structure of glucose:
- There are 5 `-OH` groups present.

### Step 4: Identify the `-OH` Groups in Fructose
In the structure of fructose:
- There are 3 `-OH` groups present.

### Step 5: Count the Total `-OH` Groups
Now, we can add the `-OH` groups from both glucose and fructose:
- Glucose: 5 `-OH` groups
- Fructose: 3 `-OH` groups

Total `-OH` groups = 5 (from glucose) + 3 (from fructose) = 8 `-OH` groups.

### Final Answer
Thus, there are **8 `-OH` groups** present in one molecule of sucrose.

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