Products of the reaction which is given below will be
`CH_(3)-underset(CH_(3))underset("| ")"C "=CH-CH_(3)overset((i)OsO_(4)(ii)aq. NaHSO_(3))underset((iii)NaIO_(4))rarr`

Options

A. Vic diol
B. Vic dicarbonyl compound
C. `CH_(3)-overset(O)overset(||)C-CH_(3) and CH_(3)-CHO`
D. `CH_(3)-overset(O)overset(||)C-CH_(3) and CH_(3)-COOH`

Answer

To determine the products of the given reaction, we will analyze the reaction step by step.

### Step 1: Identify the Starting Compound
The starting compound is 2,3-dimethyl-2-butene, which has the structure:
```
CH3
|
CH3 - C = CH - CH3
```

### Step 2: Understand the Reagents
The reagents used in the reaction are:
1. **OsO4 (Osmium Tetroxide)** - This reagent is used for the syn-dihydroxylation of alkenes, adding two hydroxyl groups across the double bond.
2. **NaHSO3 (Sodium Bisulfite)** - This is used to quench the reaction and help in the isolation of the diol formed.
3. **NaIO4 (Sodium Periodate)** - This reagent cleaves the diol formed into carbonyl compounds (aldehydes and ketones).

### Step 3: Reaction Mechanism
1. **Dihydroxylation**: The alkene reacts with OsO4 to form a cyclic osmate ester, which upon hydrolysis with NaHSO3 leads to the formation of a vicinal diol (two hydroxyl groups on adjacent carbons).

The product after this step will be:
```
OH
|
CH3 - C - CH - CH3
|
OH
```

2. **Cleavage with NaIO4**: The vicinal diol undergoes oxidative cleavage with sodium periodate, breaking the C-C bond between the two carbons that were originally part of the double bond. This will yield:
- A ketone from the carbon chain on one side (acetone).
- An aldehyde from the carbon chain on the other side (acetaldehyde).

### Step 4: Final Products
The final products of the reaction will be:
- **Acetone (2-propanone)**: CH3-CO-CH3
- **Acetaldehyde (ethanal)**: CH3-CHO

### Conclusion
Thus, the products of the reaction are acetone and acetaldehyde.