How many acidic H - atoms are present in the compound
`CH_3CH(OH)CH_(2)CH_2NH_2` that can react with `overset(Theta)R` of `R - MgX` to give alkane.

Answer

To determine how many acidic hydrogen atoms are present in the compound \( CH_3CH(OH)CH_2CH_2NH_2 \) that can react with a Grignard reagent \( R-MgX \) to give an alkane, we will analyze the structure of the compound step by step.

### Step 1: Identify the structure of the compound
The compound \( CH_3CH(OH)CH_2CH_2NH_2 \) can be broken down as follows:
- \( CH_3 \) (methyl group)
- \( CH(OH) \) (a carbon with a hydroxyl group, indicating the presence of an alcohol)
- \( CH_2 \) (a methylene group)
- \( CH_2NH_2 \) (a methylene group attached to an amine)

### Step 2: Identify the functional groups
In the compound, we have:
- One hydroxyl group (-OH) from the alcohol
- One amine group (-NH2) from the primary amine

### Step 3: Determine the acidic hydrogen atoms
Acidic hydrogen atoms are those that can be released as protons (H⁺) and can react with Grignard reagents. The acidic hydrogen atoms in this compound are:
- The hydrogen atom from the hydroxyl group (-OH) is acidic.
- The two hydrogen atoms from the amine group (-NH2) are also acidic.

### Step 4: Count the acidic hydrogen atoms
Now, we will count the acidic hydrogen atoms:
- From the -OH group: 1 acidic hydrogen
- From the -NH2 group: 2 acidic hydrogens

Adding these together gives:
\[ 1 \text{ (from -OH)} + 2 \text{ (from -NH2)} = 3 \text{ acidic hydrogen atoms} \]

### Conclusion
The total number of acidic hydrogen atoms in the compound \( CH_3CH(OH)CH_2CH_2NH_2 \) that can react with \( R-MgX \) is **3**.

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