If `XeOF_(4)` how many angles are of `90^(@)`?

Answer

To determine how many angles of 90 degrees are present in the molecule XeOF₄ (xenon oxytetrafluoride), we can follow these steps:

### Step 1: Determine the hybridization of XeOF₄
- Xenon (Xe) is the central atom in the molecule.
- It has 4 fluorine (F) atoms and 1 oxygen (O) atom bonded to it.
- To find the hybridization, we count the total number of bonding pairs and lone pairs around xenon.

### Step 2: Count the valence electrons
- Xenon has 8 valence electrons.
- Each fluorine contributes 1 electron (4 F atoms contribute 4 electrons).
- Oxygen typically contributes 2 electrons (in a double bond).
- Total electrons = 8 (from Xe) + 4 (from F) + 2 (from O) = 14 electrons.

### Step 3: Determine the number of bonding pairs and lone pairs
- Xenon forms 4 single bonds with fluorine and 1 double bond with oxygen.
- This results in 4 bonding pairs (from F) and 1 bonding pair (from O) = 5 bonding pairs.
- Since xenon has 8 valence electrons and uses 10 electrons for bonding (4 for F and 2 for O), it has 1 lone pair remaining.

### Step 4: Identify the molecular geometry
- With 5 bonding pairs and 1 lone pair, the molecular geometry can be determined using VSEPR theory.
- The arrangement of 5 bonding pairs and 1 lone pair corresponds to a square pyramidal shape.

### Step 5: Analyze the bond angles
- In a square pyramidal geometry, the bond angles between the fluorine atoms in the base are 90 degrees.
- However, the presence of the lone pair affects the angles.
- The angles between the lone pair and the bonding pairs are not 90 degrees due to the repulsion caused by the lone pair.

### Step 6: Conclusion
- In the case of XeOF₄, while there are positions where 90-degree angles could theoretically exist, the lone pair's influence means that there are no angles that are exactly 90 degrees.
- Therefore, the number of angles that are 90 degrees in XeOF₄ is **0**.

### Final Answer
The number of angles of 90 degrees in XeOF₄ is **0**.

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