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Among oxyacids of nitrogen HNO(2) is uns...

Among oxyacids of nitrogen `HNO_(2)` is unstable, it can acts as

A

Oxidising agent

B

Reducing agent

C

Oxidising agent and Reducing agent

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To solve the question regarding the behavior of nitrous acid (HNO₂) as an oxidizing agent, reducing agent, or both, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Oxidation State of Nitrogen in HNO₂**: - In HNO₂, the oxidation state of nitrogen can be calculated as follows: - Oxygen (O) has an oxidation state of -2. - There are two oxygen atoms, contributing a total of -4. - Hydrogen (H) has an oxidation state of +1. - Let the oxidation state of nitrogen (N) be x. - The overall charge of the molecule is neutral (0). - Therefore, the equation can be set up as: \[ x + 1 + (-4) = 0 \implies x - 3 = 0 \implies x = +3 \] - Thus, the oxidation state of nitrogen in HNO₂ is +3. **Hint**: Remember that the sum of oxidation states in a neutral compound is zero. 2. **Determine the Range of Oxidation States for Nitrogen**: - The highest oxidation state of nitrogen is +5 (in nitric acid, HNO₃). - The lowest oxidation state of nitrogen is -3 (in ammonia, NH₃). - Since +3 is between -3 and +5, HNO₂ can potentially act as both an oxidizing agent and a reducing agent. **Hint**: Identify the highest and lowest oxidation states of an element to determine its potential as an oxidizing or reducing agent. 3. **Analyze the Behavior of HNO₂**: - **As an Oxidizing Agent**: - HNO₂ can oxidize other substances. For example, it can oxidize hydrogen sulfide (H₂S) to sulfur (S): \[ 2 \text{HNO}_2 + \text{H}_2\text{S} \rightarrow \text{S} + 2 \text{H}_2\text{O} + 2 \text{NO} \] - In this reaction, H₂S is oxidized (the oxidation state of sulfur changes from -2 to 0). **Hint**: Look for reactions where the substance gains oxygen or loses electrons to identify oxidizing behavior. 4. **As a Reducing Agent**: - HNO₂ can also act as a reducing agent. For example, it can reduce bromine (Br₂) to hydrobromic acid (HBr): \[ \text{HNO}_2 + \text{Br}_2 + \text{H}_2\text{O} \rightarrow 2 \text{HBr} + \text{HNO}_3 \] - In this reaction, bromine is reduced (the oxidation state of bromine changes from 0 to -1). **Hint**: Identify reactions where the substance loses oxygen or gains electrons to determine reducing behavior. 5. **Conclusion**: - Since HNO₂ can act as both an oxidizing agent and a reducing agent, the correct answer to the question is that HNO₂ acts as both. ### Final Answer: HNO₂ can act as both an oxidizing agent and a reducing agent.
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