Home
Class 12
CHEMISTRY
For hypothetical reversible reaction 1...

For hypothetical reversible reaction
`1//2A_(2)(g) +3//2B_(2)(g) rarr AB_(3)(g), DeltaH =- 20 kJ` if standard entropies of `A_(2),B_(2)`, and `AB_(3)` are `60,40` and `50JK^(-1) mol^(-1)` respectively. The above reaction will be equilibrium at

A

1.732

B

3

C

`1.02xx10^(-4)`

D

`3.4xx10^(5)`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

For reversible reaction : X_((g))+3Y_((g))hArr 2Z_((g)), DeltaH=-"40 kJ" Standard entropies of X, Y and Z are 60, 40and "50 J K"^(-1)",ol"^(-1) respectively. The temperature at which the above reaction is in equilibrium is

For the reaction (1)/(2) N_(2)(g) + (3)/(2) H_(2)(g) rarr NH_(3)(g), DeltaH =-30 KJ to be at equilibrium at 477^(@) C. If standard entropy of N_(2)(g) and NH_(3)(g) are 60 and 50 "J" "mole"^(-1)K^(-1) respectively then calculate the standard entropy of H_(2)(g) in "J mole"^(-1) K^(-1).

For a hypothetical reaction of kind. AB_(2)(g)+1/2 B_(2)(g) hArr AB_(3)(g), DeltaH=-x kJ More AB_(3) could be produceed at equilibrium by

For the reaction, 2NO_(g) + O_(2)(g) rarr 2NO_(2)(g) Calculate DeltaG at 700K when enthalpy and entropy changes are -113.0 kJ mol^(-1) and -145 J K^(-1) mol^(-1) , respectively.

The enthalpy and entropy change for the reaction, Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g) are 30KJmol^(-1) and 105JK^(-1)mol^(-1) respectively. The temperature at which the reaction will be in equilibrium is:

In a reaction A_(2)(g)+4B_(2)(g) hArr 2AB_(4)(g), DeltaH lt 0 . The formation of AB_(4) is not favoured by

The enthalpy and entropy change for the reaction: Br_(2)(l) + Cl_(2)(g) to 2BrCl(g) are 30 kJ mol^(-1) and 105 JK^(-1) mol^(-1) respectively. The temperature at which the reaction will be in equilibrium is:-

The enthalpy and entropy change for the reaction, Br_(2)(l)+Cl_(2)(g)rarr2BrCl(g) are 30KJmol^(-1) and 105JK^(-1)mol^(-1) respectively. The temperature at which the raction will be in equilibrium is:

The enthalpy and entropy change for the reaction Br_(2)(l) + Cl_(2)(g) rightarrow 2BrCl(g) are 40 kJ mol^(-1) and 110 JK^(-1) mol ^(-1) repectively. The temperature at which the reaction will be in equilibrium is

For the reaction N_(2)(g) + 3H_(2)(g) rarr 2NH_(3)(g) , DeltaH = -93.6 KJ mol^(-1) the formation of NH_(3) is expected to increase at :