When the following aldohexose exists in Pyranose from, the total number of stereoisomers in its pyranose form is

Answer

To determine the total number of stereoisomers for an aldohexose (specifically glucose) in its pyranose form, we can follow these steps:

### Step 1: Identify the Structure of Glucose
Glucose is an aldohexose, meaning it contains an aldehyde group and six carbon atoms. In its pyranose form, glucose forms a six-membered ring structure.

### Step 2: Draw the Pyranose Form of Glucose
The pyranose form of glucose is represented as a six-membered ring with five carbon atoms and one oxygen atom. The structure includes hydroxyl (OH) groups and hydrogen (H) atoms attached to the carbon atoms.

### Step 3: Identify Chiral Carbons
A chiral carbon is a carbon atom that is attached to four different groups. In the pyranose form of glucose, we need to identify how many chiral carbons are present.

- In the pyranose form of glucose, the chiral carbons are typically at positions 2, 3, 4, and 5.
- The carbon at position 1 (the anomeric carbon) can also be considered chiral depending on whether it is in the alpha or beta form.

### Step 4: Count the Number of Chiral Carbons
In the case of glucose in its pyranose form, we have:
- Carbon 1 (anomeric carbon)
- Carbon 2
- Carbon 3
- Carbon 4
- Carbon 5

Thus, there are a total of **5 chiral carbons**.

### Step 5: Calculate the Number of Stereoisomers
The number of stereoisomers can be calculated using the formula:
\[ \text{Number of stereoisomers} = 2^n \]
where \( n \) is the number of chiral carbons.

Substituting the value of \( n \):
\[ \text{Number of stereoisomers} = 2^5 = 32 \]

### Conclusion
The total number of stereoisomers for glucose in its pyranose form is **32**.

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