Home
Class 12
CHEMISTRY
Formation of polyethylene from calcium c...

Formation of polyethylene from calcium carbide takes place as follows
`CaC_(2)+2 H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)`
`C_(2)H_(2)+H_(2) rarr C_(2)H_(2)`
`N(C_(2)H_(4)) rarr (-CH_(2)-CH_(2)-)_(n)`
The amount of polyethylene obtained from `64.0 kg CaC_(2) ` is

Text Solution

Verified by Experts

The correct Answer is:
28
Promotional Banner

Similar Questions

Explore conceptually related problems

The fomation of polyethylene from calcium carbide takes place as follows: CaC_(2)+2H_(2)OrarrCa(OH_(2))+C_(2)H_(2) C_(2)H_(2)+H_(2)rarrC_(2)H_(4) The amount of polyethylene obtained form64kg of CaC_(2)

Polythene can be produced from calcium carbide according to the following sequence of reactions. CaC_(2)+2H_(2)Orarr Ca(OH)_(2)+C_(2)H_(2), C_(2)H_(2)+H_(2)rarr C_(2)H_(4), nC_(2)H_(4)rarr(C_(2)H_(4))n The mass of polythene which can be produced from "20.0 kg of "CaC_(2) is :

Complete the following reactions (a) XeF_(4) + H_(2)O rarr (b ) XeF_(6) + H_(2) rarr (c) XeF_(6) + H_(2)O rarr (d) XeF_(6) + NH_(3) rarr

Calculate the molecular masses of H_(2), O_(2), Cl_(2), CO_(2), CH_(4), C_(2)H_(6), C_(2)H_(4), NH_(3), CH_(3)OH .

CH_(3)-CH=CH_(2) + B_(2)H_(6) rarr ?+ H_(2) O_(2) / OH^(-) rarr (A). (A) is......

C_(6)H_(5)CH_(2)Cl + X rarr C_(6)H_(5)CH_(2) NH_(2) + Y The compounds X and Y are

CaC_(2) and H_(2)O react to produce:

The volume of ascetylene at NTP produced by reaction of 50 gm of CaC_(2) with water is : CaC_(2)+H_(2)O rarr Ca(OH)_(2)+C_(2)H_(2)

Be_(2)C+H_(2)OrarrBeO+X CaC_(2)+H_(2)OrarrCa(OH)_(2)+Y Mg_(2)C_(3)+H_(2)OrarrMg(OH)_(2)+Z Identify (X),(Y) and (Z) .

Arrange the following compounds in the increasing order of their boiling points: CH_(3)CH_(2)CH_(2)CHO, CH_(3)CH_(2)CH_(2)CH_(2)OH, H_(5)C_(2)-O-C_(2)H_(5),CH_(3)CH_(2)CH_(2)CH_(3)