Home
Class 12
CHEMISTRY
For the reaction: aA + bB rarr cC+dD R...

For the reaction: `aA + bB rarr cC+dD`
Rate `= (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt)`
In the following reaction,
`xA rarr yB`
`log.[-(d[A])/(dt)] = log.[(d[B])/(dt)] + 0.3`
where negative isgn indicates rate of disappearance of the reactant. Thus, `x:y` is:

A

`2:1`

B

`1:2`

C

`3:1`

D

`3:10`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) A reaction follows the given concentration-time graph. The rate for this reaction at 20 s will be

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) The rate of formation of SO_(3) in the following reaction 2SO_(2) + O_(2) rarr 2SO_(3) is 100 g min^(-1) . Hence the rate of disappearance of O_(2) is

In the following reaction, xA rarryB log_(10)[-(d[A])/(dt)]=log_(10)[(d([B]))/(dt)]+0.3010 ‘A’ and ‘B’ respectively can be:

For the reaction: aA + bB rarr cC+dD Rate = (dx)/(dt) = (-1)/(a)(d[A])/(dt) = (-1)/(b)(d[B])/(dt) = (1)/( c)(d[C])/(dt) = (1)/(d)(d[D])/(dt) For reaction 3BrO^(ɵ) rarr BrO_(3)^(ɵ) + 2Br^(ɵ) , the value of rate constant at 80^(@)C in the rate law for -(d[BrO^(ɵ)])/(dt) was found to be 0.054 L mol^(-1)s^(-1) . The rate constant (k) for the reaction in terms of (d[BrO_(3)^(ɵ)])/(dt) is

For the reaction : aA to bB , it is given that log[(-dA)/(dt)] = log [(dB)/(dt)] + 0.6020 . What is a : b is ?

The rate of a reaction is expressed in different ways as follows: +(1)/(2)(d[C])/(dt)=-(1)/(2)(d[D])/(dt)=+(1)/(3)(d[A])/(dt)=-(d[B])/(dt) the reaction is

The rate of a reaction is expressed in different ways as follows: +(1)/(2)(d[C])/(dt)=-(1)/(3)(d[D])/(dt)=+(1)/(4)(d[A])/(dt)=-(d[B])/(dt) the reaction is

In a reaction, aA+bBrarrcC+dD rate =-1/a(d[A])/(dt) , the - ve sign in it represents

Mechanism of the reaction is: What is (a) (-d[A])/(dt) , (b) (d[A_(1)])/(dt)

In the reaction 3Ararr2B , rate of reaction +(d[B])/(dt) is equal to :