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The root mean square speed of N(2) molec...

The root mean square speed of `N_(2)` molecules in sample at temperature T is 'x'. If the temperature is doubled, then nitrogen molecules dissociate into atoms, the root mean square speedof nitrogen atoms becomes n times of 'x' find the value of n here?

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To solve the problem, we will follow these steps: ### Step 1: Understanding the root mean square speed formula The root mean square speed (\( V_{rms} \)) of gas molecules is given by the formula: \[ V_{rms} = \sqrt{\frac{3RT}{M}} \] where: - \( R \) is the universal gas constant, - \( T \) is the absolute temperature, - \( M \) is the molar mass of the gas. ### Step 2: Initial conditions We are given that the root mean square speed of \( N_2 \) molecules at temperature \( T \) is \( x \). Therefore, we can write: \[ x = \sqrt{\frac{3RT}{M}} \] ### Step 3: Doubling the temperature If the temperature is doubled, the new temperature \( T' \) becomes: \[ T' = 2T \] ### Step 4: Change in molecular mass due to dissociation When the nitrogen molecules dissociate into atoms, the molecular mass changes. The molar mass of \( N_2 \) is \( M \), and when it dissociates into nitrogen atoms, the molar mass of each nitrogen atom becomes \( \frac{M}{2} \). ### Step 5: New root mean square speed calculation Now, we can calculate the new root mean square speed (\( V'_{rms} \)) after the temperature is doubled and the nitrogen molecules dissociate: \[ V'_{rms} = \sqrt{\frac{3R(2T)}{\frac{M}{2}}} \] This simplifies to: \[ V'_{rms} = \sqrt{\frac{3R \cdot 2T \cdot 2}{M}} = \sqrt{\frac{6RT}{M}} = \sqrt{4} \cdot \sqrt{\frac{3RT}{M}} = 2 \cdot x \] ### Step 6: Relating the new speed to \( n \) According to the problem, the new root mean square speed of nitrogen atoms becomes \( n \) times \( x \): \[ V'_{rms} = n \cdot x \] From our calculation, we found that: \[ V'_{rms} = 2x \] Thus, we can equate: \[ n \cdot x = 2x \] ### Step 7: Solving for \( n \) Dividing both sides by \( x \) (assuming \( x \neq 0 \)): \[ n = 2 \] ### Conclusion The value of \( n \) is: \[ \boxed{2} \]
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