Which of the following statement in correct with reference of `RS^(Theta) and RO^(Theta).`?

Options

A. `RS^(Theta)` is less basic and less nucleophilic than `RO^(Theta)`
B. `RS^(Theta)` is less basic and more nucleophilic than `RO^(Theta)`
C. `RS^(Theta)` is less basic and more nucleophilic than `RO^(Theta)`
D. `RS^(Theta)` is more basic but less nucleophilic than `RO^(Theta)`

Answer

To determine which statement is correct regarding \( RS^- \) and \( RO^- \), we need to analyze their basicity and nucleophilicity.

### Step 1: Understand the Definitions
- **Nucleophilicity** refers to the ability of a species to donate electrons to a positively charged or electron-deficient species. A good nucleophile is typically less electronegative.
- **Basicity** refers to the ability of a species to accept protons (H+). A stronger base is usually more electronegative.

### Step 2: Compare Electronegativity
- Oxygen (O) is more electronegative than sulfur (S). Therefore, \( RO^- \) (alkoxide ion) is more electronegative than \( RS^- \) (thiolate ion).

### Step 3: Analyze Nucleophilicity
- Since \( RS^- \) is less electronegative than \( RO^- \), it is a better nucleophile. This is because less electronegative species hold onto their electrons less tightly and can donate them more readily.

### Step 4: Analyze Basicity
- \( RO^- \) being more electronegative means it can attract protons (H+) more effectively than \( RS^- \). Thus, \( RO^- \) is a stronger base compared to \( RS^- \).

### Conclusion
From the analysis:
- \( RS^- \) is a better nucleophile than \( RO^- \) because it is less electronegative.
- \( RO^- \) is a stronger base than \( RS^- \) because it is more electronegative.

### Final Statement
The correct statement is that \( RS^- \) is less basic and more nucleophilic than \( RO^- \).

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