Find out total number of compound (s) in which at least half of `Cl^(-)` are ionizable `CrCl_(3).6NH_(3), CrCl_(3).5NH_(3),CrCl_(3).4NH_(3),CrCl_(3).3NH_(3),PtCl_(4).6NH_(3),PtCl_(4).5NH_(3)`
.`PtCl_(4).4NH_(3),PtCl_(4).3NH_(3),PtCl_(4).2NH_(3)`

Answer

To find the total number of compounds in which at least half of the chloride ions (Cl^(-)) are ionizable, we will analyze each compound step by step.

### Step-by-Step Solution:

1. **Identify the Compounds:**
The compounds given are:
- CrCl₃·6NH₃
- CrCl₃·5NH₃
- CrCl₃·4NH₃
- CrCl₃·3NH₃
- PtCl₄·6NH₃
- PtCl₄·5NH₃
- PtCl₄·4NH₃
- PtCl₄·3NH₃
- PtCl₄·2NH₃

2. **Analyze Each Compound:**
- **CrCl₃·6NH₃:**
- Structure: Cr(NH₃)₆Cl₃
- Ionizable Cl: 3 (all are ionizable)
- Half of Cl: 1.5
- Result: More than half are ionizable. **(Count: 1)**

- **CrCl₃·5NH₃:**
- Structure: Cr(NH₃)₅Cl₂
- Ionizable Cl: 2 (2 out of 3 are ionizable)
- Half of Cl: 1.5
- Result: More than half are ionizable. **(Count: 2)**

- **CrCl₃·4NH₃:**
- Structure: Cr(NH₃)₄Cl₂
- Ionizable Cl: 2 (2 out of 3 are ionizable)
- Half of Cl: 1.5
- Result: More than half are ionizable. **(Count: 3)**

- **CrCl₃·3NH₃:**
- Structure: Cr(NH₃)₃Cl₃
- Ionizable Cl: 3 (all are ionizable)
- Half of Cl: 1.5
- Result: More than half are ionizable. **(Count: 4)**

- **PtCl₄·6NH₃:**
- Structure: Pt(NH₃)₆Cl₄
- Ionizable Cl: 4 (all are ionizable)
- Half of Cl: 2
- Result: More than half are ionizable. **(Count: 5)**

- **PtCl₄·5NH₃:**
- Structure: Pt(NH₃)₅Cl₃
- Ionizable Cl: 3 (3 out of 4 are ionizable)
- Half of Cl: 2
- Result: More than half are ionizable. **(Count: 6)**

- **PtCl₄·4NH₃:**
- Structure: Pt(NH₃)₄Cl₂
- Ionizable Cl: 2 (2 out of 4 are ionizable)
- Half of Cl: 2
- Result: Exactly half are ionizable. **(Count: 7)**

- **PtCl₄·3NH₃:**
- Structure: Pt(NH₃)₃Cl₃
- Ionizable Cl: 3 (all are ionizable)
- Half of Cl: 2
- Result: More than half are ionizable. **(Count: 8)**

- **PtCl₄·2NH₃:**
- Structure: Pt(NH₃)₂Cl₂
- Ionizable Cl: 2 (2 out of 4 are ionizable)
- Half of Cl: 2
- Result: Exactly half are ionizable. **(Count: 9)**

3. **Total Count:**
The total number of compounds in which at least half of the chloride ions are ionizable is **9**.

### Final Answer:
The total number of compounds in which at least half of Cl^(-) are ionizable is **9**.