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C(2)H(2) underset( H(2)SO(4))overset( Hg...

`C_(2)H_(2) underset( H_(2)SO_(4))overset( Hg(OH)_(2) 1%) (rarr) A overset( [O])(rarr) B`, B is `:`

A

An acid

B

An aldehyde

C

A ketone

D

Ethanol

Text Solution

AI Generated Solution

The correct Answer is:
To solve the given question step by step, we will analyze the reaction of acetylene (C₂H₂) with mercuric hydroxide (Hg(OH)₂) in the presence of sulfuric acid (H₂SO₄), followed by oxidation. ### Step 1: Identify the Reactants The reactants given are: - Acetylene (C₂H₂) - Mercuric hydroxide (Hg(OH)₂) - 1% - Sulfuric acid (H₂SO₄) ### Step 2: Reaction of Acetylene with Hg(OH)₂ and H₂SO₄ When acetylene (C₂H₂) reacts with mercuric hydroxide and sulfuric acid, it undergoes hydration to form an intermediate product. The reaction can be represented as follows: \[ \text{C}_2\text{H}_2 + \text{Hg(OH)}_2 + \text{H}_2\text{SO}_4 \rightarrow \text{C}_2\text{H}_5\text{OH} \] However, this intermediate product (vinyl alcohol, CH₂=CHOH) is unstable and will dehydrate to form an aldehyde. The dehydration leads to the formation of: \[ \text{C}_2\text{H}_5\text{OH} \rightarrow \text{CH}_3\text{CHO} \] Thus, product A is acetaldehyde (CH₃CHO). ### Step 3: Oxidation of Product A Next, we oxidize product A (acetaldehyde) using an oxidizing agent (represented as [O]). The oxidation of acetaldehyde leads to the formation of acetic acid (CH₃COOH): \[ \text{CH}_3\text{CHO} + [O] \rightarrow \text{CH}_3\text{COOH} \] Thus, product B is acetic acid (CH₃COOH). ### Final Products - Product A: Acetaldehyde (CH₃CHO) - Product B: Acetic acid (CH₃COOH) ### Conclusion The final answer is that product B is acetic acid (CH₃COOH). ---
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