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All the students of a class performed po...

All the students of a class performed poorly in Mathematics. The teacher decided to give grace marks of 12 to the entire class. Which of the following statistical measures will not change even after the grace marks were given?

A

Median

B

Mode

C

Variance

D

Mean

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze how the grace marks affect different statistical measures: mean, median, mode, and variance. ### Step 1: Understanding the Statistical Measures - **Mean**: The average of all the marks. - **Median**: The middle value when all marks are arranged in order. - **Mode**: The most frequently occurring mark. - **Variance**: A measure of how much the marks vary from the mean. ### Step 2: Assigning Marks Let's assume we have 5 students with the following marks: - \( x_1, x_2, x_3, x_4, x_5 \) (where \( x_1 < x_2 < x_3 < x_4 \leq x_5 \)) ### Step 3: Calculating the Mean The mean before the grace marks is: \[ \text{Mean} = \frac{x_1 + x_2 + x_3 + x_4 + x_5}{5} \] After adding 12 grace marks to each student, the new marks become: - \( x_1 + 12, x_2 + 12, x_3 + 12, x_4 + 12, x_5 + 12 \) The new mean will be: \[ \text{New Mean} = \frac{(x_1 + 12) + (x_2 + 12) + (x_3 + 12) + (x_4 + 12) + (x_5 + 12)}{5} = \frac{x_1 + x_2 + x_3 + x_4 + x_5 + 60}{5} = \text{Mean} + 12 \] Thus, the mean changes. ### Step 4: Calculating the Median The median before the grace marks is: \[ \text{Median} = x_3 \] After the grace marks, the new median will be: \[ \text{New Median} = x_3 + 12 \] Thus, the median changes. ### Step 5: Calculating the Mode The mode before the grace marks is the most frequently occurring mark, which we can denote as \( x_4 \) (if it occurs most often). After adding grace marks, the new mode will be: \[ \text{New Mode} = x_4 + 12 \] Thus, the mode changes. ### Step 6: Calculating the Variance Variance is calculated as: \[ \text{Variance} = \frac{\sum (x_i - \text{Mean})^2}{n} \] After adding 12 to each score, the new variance will be: \[ \text{New Variance} = \frac{\sum ((x_i + 12) - (\text{Mean} + 12))^2}{n} = \frac{\sum (x_i - \text{Mean})^2}{n} \] Thus, the variance remains unchanged. ### Conclusion The statistical measure that does not change after adding grace marks is **Variance**.
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