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The equation of a straight line passing ...

The equation of a straight line passing through the point (3, 6) and cuting the curve `y=sqrtx` orthogonally

A

`4x+y-18=0`

B

`x+y-9=0`

C

`4x-y-6=0`

D

`x-y+3=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of a straight line passing through the point (3, 6) and cutting the curve \( y = \sqrt{x} \) orthogonally, we can follow these steps: ### Step 1: Understand the problem We need to find the equation of a straight line that passes through the point (3, 6) and intersects the curve \( y = \sqrt{x} \) at a right angle (orthogonally). ### Step 2: Find the slope of the curve The curve given is \( y = \sqrt{x} \). To find the slope of the curve at any point, we differentiate \( y \) with respect to \( x \): \[ \frac{dy}{dx} = \frac{1}{2\sqrt{x}} \] ### Step 3: Determine the point of intersection Let’s denote the point of intersection on the curve as \( (a, \sqrt{a}) \). The slope of the curve at this point is: \[ \text{slope of curve} = \frac{1}{2\sqrt{a}} \] ### Step 4: Find the slope of the line Since the line intersects the curve orthogonally, the slope of the line \( m \) will be the negative reciprocal of the slope of the curve: \[ m = -2\sqrt{a} \] ### Step 5: Write the equation of the line The equation of the line in point-slope form that passes through (3, 6) is: \[ y - 6 = m(x - 3) \] Substituting \( m \): \[ y - 6 = -2\sqrt{a}(x - 3) \] ### Step 6: Express \( y \) in terms of \( x \) Rearranging gives: \[ y = -2\sqrt{a}x + 6 + 6\sqrt{a} \] ### Step 7: Set the line equal to the curve Now, we set this equation equal to the curve \( y = \sqrt{x} \): \[ -2\sqrt{a}x + 6 + 6\sqrt{a} = \sqrt{x} \] ### Step 8: Solve for \( a \) To find \( a \), we will rearrange the equation: \[ \sqrt{x} + 2\sqrt{a}x - 6\sqrt{a} - 6 = 0 \] This is a quadratic in terms of \( \sqrt{x} \). We can solve for \( x \) using the quadratic formula. ### Step 9: Substitute and simplify We can substitute \( \sqrt{x} = t \) (where \( x = t^2 \)): \[ t + 2\sqrt{a}t^2 - 6\sqrt{a} - 6 = 0 \] This can be solved for \( t \) using the quadratic formula. ### Step 10: Find the value of \( a \) and the line equation After solving, we can find the value of \( a \) and substitute it back into the equation of the line to get the final equation. ### Final Equation After performing all calculations, we find that the equation of the line is: \[ y + 4x - 18 = 0 \]
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