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If B=int(1)/(e^(x)+1)dx=-f(x)+C, where C...

If `B=int(1)/(e^(x)+1)dx=-f(x)+C`, where C is the constant of integration and `e^(f(0))=2`, then the value of `e^(f(-1))` is

A

4

B

`e+1`

C

`2e`

D

0

Text Solution

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The correct Answer is:
B
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