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The integral I=int[xe^(x^(2))(sinx^(2)+c...

The integral `I=int[xe^(x^(2))(sinx^(2)+cosx^(2))]dx =f(x)+c`, (where, c is the constant of integration). Then, f(x) can be

A

`e^(x)sin(x^(2))`

B

`e^(x^(2))sin(x)`

C

`e^(x^(2))((x^(2))/(2))`

D

`(1)/(2)e^(x^(2))sin(x^(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the integral \[ I = \int x e^{x^2} (\sin x^2 + \cos x^2) \, dx, \] we can follow these steps: ### Step 1: Substitution Let \( t = x^2 \). Then, the differential \( dt = 2x \, dx \) implies that \( x \, dx = \frac{dt}{2} \). ### Step 2: Rewrite the Integral Substituting \( t \) into the integral, we have: \[ I = \int x e^{x^2} (\sin x^2 + \cos x^2) \, dx = \int e^t (\sin t + \cos t) \frac{dt}{2}. \] ### Step 3: Factor Out Constants We can factor out the constant \( \frac{1}{2} \): \[ I = \frac{1}{2} \int e^t (\sin t + \cos t) \, dt. \] ### Step 4: Integration by Parts Next, we can use integration by parts. We know the formula: \[ \int e^x f(x) \, dx = e^x f(x) - \int e^x f'(x) \, dx. \] Let \( f(t) = \sin t + \cos t \). Then, \( f'(t) = \cos t - \sin t \). ### Step 5: Apply Integration by Parts Applying integration by parts, we have: \[ \int e^t (\sin t + \cos t) \, dt = e^t (\sin t + \cos t) - \int e^t (\cos t - \sin t) \, dt. \] ### Step 6: Simplify the Integral Now we need to evaluate the integral \( \int e^t (\cos t - \sin t) \, dt \). We can apply integration by parts again for this integral. ### Step 7: Combine Results After performing the integration by parts twice, we will combine the results. The final result will be in terms of \( e^t \), which we will substitute back to \( x \) using \( t = x^2 \). ### Step 8: Final Expression The integral \( I \) will yield a function \( f(x) \) plus a constant of integration \( c \): \[ I = \frac{1}{2} e^{x^2} (\sin x^2 + \cos x^2) + C. \] Thus, we can conclude that: \[ f(x) = \frac{1}{2} e^{x^2} (\sin x^2 + \cos x^2). \]
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