Home
Class 12
MATHS
The mean and variance of 7 observations ...

The mean and variance of 7 observations are 7 and 22 respectively. If 5 of the observations are 2, 4, 10, 12, 14, then the remaining 2 observations are

A

4, 3

B

2, 5

C

6, 1

D

4, 2

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the two remaining observations given the mean and variance of a set of observations. Here’s a step-by-step breakdown of the solution: ### Step 1: Understand the Given Information We have: - Mean of 7 observations = 7 - Variance of 7 observations = 22 - 5 observations = 2, 4, 10, 12, 14 Let the remaining two observations be \( a \) and \( b \). ### Step 2: Set Up the Equation for Mean The mean is calculated as follows: \[ \text{Mean} = \frac{\text{Sum of all observations}}{\text{Number of observations}} \] Thus, we can write: \[ 7 = \frac{2 + 4 + 10 + 12 + 14 + a + b}{7} \] Calculating the sum of the known observations: \[ 2 + 4 + 10 + 12 + 14 = 42 \] Substituting this into the mean equation gives: \[ 7 = \frac{42 + a + b}{7} \] Multiplying both sides by 7: \[ 49 = 42 + a + b \] Rearranging gives us: \[ a + b = 49 - 42 = 7 \quad \text{(Equation 1)} \] ### Step 3: Set Up the Equation for Variance The variance is given by: \[ \text{Variance} = \frac{1}{n} \sum_{i=1}^{n} (x_i - \bar{x})^2 \] For our case: \[ 22 = \frac{1}{7} \left( (2 - 7)^2 + (4 - 7)^2 + (10 - 7)^2 + (12 - 7)^2 + (14 - 7)^2 + (a - 7)^2 + (b - 7)^2 \right) \] Calculating the squared differences: \[ (2 - 7)^2 = 25, \quad (4 - 7)^2 = 9, \quad (10 - 7)^2 = 9, \quad (12 - 7)^2 = 25, \quad (14 - 7)^2 = 49 \] Summing these gives: \[ 25 + 9 + 9 + 25 + 49 = 117 \] Substituting into the variance equation: \[ 22 = \frac{1}{7} (117 + (a - 7)^2 + (b - 7)^2) \] Multiplying both sides by 7: \[ 154 = 117 + (a - 7)^2 + (b - 7)^2 \] Rearranging gives: \[ (a - 7)^2 + (b - 7)^2 = 154 - 117 = 37 \quad \text{(Equation 2)} \] ### Step 4: Solve the System of Equations From Equation 1, we have: \[ a + b = 7 \] From Equation 2, we can expand: \[ (a - 7)^2 + (b - 7)^2 = (a^2 - 14a + 49) + (b^2 - 14b + 49) = 37 \] Substituting \( b = 7 - a \) into the equation: \[ (a - 7)^2 + ((7 - a) - 7)^2 = 37 \] This simplifies to: \[ (a - 7)^2 + (-a)^2 = 37 \] Expanding gives: \[ (a - 7)^2 + a^2 = 37 \] \[ a^2 - 14a + 49 + a^2 = 37 \] Combining like terms: \[ 2a^2 - 14a + 49 - 37 = 0 \] \[ 2a^2 - 14a + 12 = 0 \] Dividing by 2: \[ a^2 - 7a + 6 = 0 \] Factoring gives: \[ (a - 1)(a - 6) = 0 \] Thus, \( a = 1 \) or \( a = 6 \). ### Step 5: Find Corresponding Values of \( b \) If \( a = 1 \), then \( b = 7 - 1 = 6 \). If \( a = 6 \), then \( b = 7 - 6 = 1 \). ### Conclusion The remaining two observations are \( 1 \) and \( 6 \).
Promotional Banner

Similar Questions

Explore conceptually related problems

The mean and variance of 7 observations are 8 and 16, respectively. If five of the observations are 2, 4, 10, 12, 14. Find the remaining two observations.

The mean and variance of seven observations are 8 and 16 respectively. If five of these are 2,4,10,12 and 14, then find the remaining two observations.

The mean and variance of eight observations are 9 and 9.25, respectively. If six of the observations are 6, 7, 10, 12, 12 and 13, find the remaining two observations.

The mean and variance of 7 observation is 8 and 16. If five of the observations are 2, 4, 10, 12, 14. Find the remaining two observations.

The mean and variance of 5 observations are respectively 4.4 and 8.24. If three observation are 1,2 and 4 then find the remaining two observations.

The mean and variance of 8 observations are respectively 9 and 9.25. If six observations are 4,6,7,8,12 and 13 then find the remaining two observations.

Mean and variance of five observations are 4 and 5.2 respectively. If three of these observations are 3, 4, 4 then find absolute difference between the other two observations (A) 3 (B) 7 (C) 2 (D) 5

Mean and variance of five observations are 4 and 5.2 respectively. If three of these observations are 3, 4, 4 then find absolute difference between the other two observations (A) 3 (B) 7 (C) 2 (D) 5

The mean of five observations is 4 and their variance is 5.2. If three of these observations are 2, 4 and 6, then the other two observations are :

The mean of 5 observations is 4.4 and variance is 8.24. If three of the five observations are 1,2, and 6 then remaining two observations are (i) 9, 16 (ii) 9, 4 (iii) 81, 16 (iv) 81, 4