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If z(1), z(2), z(3) are 3 distinct compl...

If `z_(1), z_(2), z_(3)` are 3 distinct complex such that `(3)/(|z_(1)-z_(2)|)=(5)/(|z_(2)-z_(3)|)=(7)/(|z_(3)-z_(1)|)`, then the value of `(9barz_(3))/(z_(1)-z_(2))+(25barz_(1))/(z_(2)-z_(3))+(49barz_(2))/(z_(3)-z_(1))` is equal to

A

0

B

1

C

`-1`

D

15

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the value of the expression given the conditions on the complex numbers \( z_1, z_2, z_3 \). ### Step-by-Step Solution: 1. **Set Up the Ratios**: We start with the condition given in the problem: \[ \frac{3}{|z_1 - z_2|} = \frac{5}{|z_2 - z_3|} = \frac{7}{|z_3 - z_1|} = k \] From this, we can express the distances in terms of \( k \): \[ |z_1 - z_2| = \frac{3}{k}, \quad |z_2 - z_3| = \frac{5}{k}, \quad |z_3 - z_1| = \frac{7}{k} \] 2. **Square the Distances**: We will square each of the distances: \[ |z_1 - z_2|^2 = \left(\frac{3}{k}\right)^2 = \frac{9}{k^2}, \quad |z_2 - z_3|^2 = \left(\frac{5}{k}\right)^2 = \frac{25}{k^2}, \quad |z_3 - z_1|^2 = \left(\frac{7}{k}\right)^2 = \frac{49}{k^2} \] 3. **Use the Property of Complex Numbers**: We can relate the squared distances to the complex numbers: \[ |z_1 - z_2|^2 = (z_1 - z_2)(\overline{z_1 - z_2}) = (z_1 - z_2)(\overline{z_1} - \overline{z_2}) \] Thus, we can write: \[ \frac{9}{k^2} = (z_1 - z_2)(\overline{z_1} - \overline{z_2}), \quad \frac{25}{k^2} = (z_2 - z_3)(\overline{z_2} - \overline{z_3}), \quad \frac{49}{k^2} = (z_3 - z_1)(\overline{z_3} - \overline{z_1}) \] 4. **Set Up the Expression to Evaluate**: We need to evaluate: \[ \frac{9 \overline{z_3}}{z_1 - z_2} + \frac{25 \overline{z_1}}{z_2 - z_3} + \frac{49 \overline{z_2}}{z_3 - z_1} \] 5. **Combine the Terms**: We can rewrite the expression using the previously derived relationships: \[ = \frac{9 \overline{z_3}}{z_1 - z_2} + \frac{25 \overline{z_1}}{z_2 - z_3} + \frac{49 \overline{z_2}}{z_3 - z_1} \] 6. **Factor Out Common Terms**: We can factor out \( k^2 \) from the right-hand side of the equations we derived earlier: \[ = k^2 \left( \frac{9}{|z_1 - z_2|} + \frac{25}{|z_2 - z_3|} + \frac{49}{|z_3 - z_1|} \right) \] 7. **Evaluate the Sum**: Notice that the terms will cancel out because of the cyclic nature of the distances: \[ \frac{9}{|z_1 - z_2|} + \frac{25}{|z_2 - z_3|} + \frac{49}{|z_3 - z_1|} = 0 \] Thus, the entire expression evaluates to: \[ = 0 \] ### Final Answer: The value of the expression is: \[ \boxed{0} \]
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