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If the product of height and square of t...

If the product of height and square of the radius of the greatest cone obtained by rotating a right - angle triangle of hypotenuse 2 meters about a side is `(k)/(3sqrt3)`, then k is equal to

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To solve the problem, we need to find the value of \( k \) given that the product of the height and the square of the radius of the greatest cone obtained by rotating a right-angle triangle of hypotenuse 2 meters about one of its sides is \( \frac{k}{3\sqrt{3}} \). ### Step-by-Step Solution: 1. **Understanding the Triangle**: We have a right-angle triangle with a hypotenuse of 2 meters. Let the sides be \( a \), \( b \), and \( c \) (where \( c \) is the hypotenuse). According to the Pythagorean theorem, we have: \[ a^2 + b^2 = c^2 \] Here, \( c = 2 \), so: \[ a^2 + b^2 = 2^2 = 4 \] 2. **Setting Up the Cone**: When we rotate the triangle about one of its sides (let's say side \( AB \)), we form a cone where: - Height \( h = a \) - Radius \( r = b \) 3. **Using Pythagorean Theorem**: From the triangle, we can express \( r \) in terms of \( h \): \[ r^2 + h^2 = 4 \implies r^2 = 4 - h^2 \] 4. **Volume of the Cone**: The volume \( V \) of the cone is given by: \[ V = \frac{1}{3} \pi r^2 h \] Substituting \( r^2 \): \[ V = \frac{1}{3} \pi (4 - h^2) h = \frac{1}{3} \pi (4h - h^3) \] 5. **Maximizing the Volume**: To find the maximum volume, we differentiate \( V \) with respect to \( h \): \[ \frac{dV}{dh} = \frac{1}{3} \pi (4 - 3h^2) \] Setting the derivative to zero for maximization: \[ 4 - 3h^2 = 0 \implies 3h^2 = 4 \implies h^2 = \frac{4}{3} \implies h = \frac{2}{\sqrt{3}} \] 6. **Finding the Radius**: Now substituting \( h \) back to find \( r^2 \): \[ r^2 = 4 - h^2 = 4 - \frac{4}{3} = \frac{12}{3} - \frac{4}{3} = \frac{8}{3} \] 7. **Calculating the Product**: The product of height and square of the radius is: \[ h \cdot r^2 = \left(\frac{2}{\sqrt{3}}\right) \cdot \left(\frac{8}{3}\right) = \frac{16}{3\sqrt{3}} \] 8. **Finding \( k \)**: According to the problem, this product equals \( \frac{k}{3\sqrt{3}} \): \[ \frac{16}{3\sqrt{3}} = \frac{k}{3\sqrt{3}} \] Therefore, \( k = 16 \). ### Final Answer: The value of \( k \) is \( \boxed{16} \).
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