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If z(i) (where i=1, 2,………………..6) be the ...

If `z_(i)` (where `i=1, 2,………………..6`) be the roots of the equation `z^(6)+z^(4)-2=0`, then `Sigma_(i=1)^(6)|z_(i)|^(4)` is equal to

A

4

B

6

C

8

D

10

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( z^6 + z^4 - 2 = 0 \) and find the sum \( \Sigma_{i=1}^{6} |z_i|^4 \), we will follow these steps: ### Step 1: Factor the equation We start with the equation: \[ z^6 + z^4 - 2 = 0 \] We can rewrite this as: \[ z^6 - 1 + z^4 - 1 = 0 \] This can be factored using the difference of cubes and squares: \[ (z^2 - 1)(z^4 + 2z^2 + 2) = 0 \] ### Step 2: Solve the first factor Setting the first factor to zero: \[ z^2 - 1 = 0 \] This gives us: \[ z = 1 \quad \text{and} \quad z = -1 \] ### Step 3: Solve the second factor Now, we solve the second factor: \[ z^4 + 2z^2 + 2 = 0 \] Let \( t = z^2 \). Then we have: \[ t^2 + 2t + 2 = 0 \] Using the quadratic formula: \[ t = \frac{-2 \pm \sqrt{2^2 - 4 \cdot 1 \cdot 2}}{2 \cdot 1} = \frac{-2 \pm \sqrt{4 - 8}}{2} = \frac{-2 \pm \sqrt{-4}}{2} = -1 \pm i \] Thus, the roots for \( z^2 \) are: \[ z^2 = -1 + i \quad \text{and} \quad z^2 = -1 - i \] ### Step 4: Find the roots \( z \) Taking square roots, we find: 1. For \( z^2 = -1 + i \): \[ z = \sqrt{-1 + i} \quad \text{and} \quad z = -\sqrt{-1 + i} \] 2. For \( z^2 = -1 - i \): \[ z = \sqrt{-1 - i} \quad \text{and} \quad z = -\sqrt{-1 - i} \] ### Step 5: Calculate the magnitudes Now we need to calculate \( |z|^4 \) for all roots: 1. For \( z = 1 \) and \( z = -1 \): \[ |z_1|^4 = 1^4 = 1 \quad \text{and} \quad |z_2|^4 = (-1)^4 = 1 \] 2. For \( z^2 = -1 + i \): \[ |z^2| = \sqrt{(-1)^2 + 1^2} = \sqrt{2} \implies |z| = \sqrt[4]{2} \implies |z|^4 = 2 \] This applies to both roots derived from \( -1 + i \). 3. For \( z^2 = -1 - i \): \[ |z^2| = \sqrt{(-1)^2 + (-1)^2} = \sqrt{2} \implies |z| = \sqrt[4]{2} \implies |z|^4 = 2 \] This applies to both roots derived from \( -1 - i \). ### Step 6: Summation of magnitudes Now we can sum the magnitudes: \[ \Sigma_{i=1}^{6} |z_i|^4 = |z_1|^4 + |z_2|^4 + |z_3|^4 + |z_4|^4 + |z_5|^4 + |z_6|^4 = 1 + 1 + 2 + 2 + 2 + 2 = 10 \] ### Final Answer Thus, the value of \( \Sigma_{i=1}^{6} |z_i|^4 \) is: \[ \boxed{10} \]
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