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If I=int(x^(3)-1)/(x^(5)+x^(4)+x+1)dx=(1...

If `I=int(x^(3)-1)/(x^(5)+x^(4)+x+1)dx=(1)/(4)ln(f(x))-ln(g(x))+c` (where, c is the constant of integration) and `f(0)=g(0)=1`,then the value of `f(1).g(1)` is equal to

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To solve the given problem step by step, we start with the integral: \[ I = \int \frac{x^3 - 1}{x^5 + x^4 + x + 1} \, dx \] We need to express this integral in terms of functions \(f(x)\) and \(g(x)\) such that: \[ I = \frac{1}{4} \ln(f(x)) - \ln(g(x)) + C \] where \(C\) is the constant of integration and \(f(0) = g(0) = 1\). ### Step 1: Simplifying the Integral First, we can factor the denominator \(x^5 + x^4 + x + 1\). We can rewrite it as: \[ x^5 + x^4 + x + 1 = x^4(x + 1) + (x + 1) = (x^4 + 1)(x + 1) \] Thus, we can rewrite the integral as: \[ I = \int \frac{x^3 - 1}{(x^4 + 1)(x + 1)} \, dx \] ### Step 2: Splitting the Integral Next, we can split the integral into two parts: \[ I = \int \frac{x^3}{(x^4 + 1)(x + 1)} \, dx - \int \frac{1}{(x^4 + 1)(x + 1)} \, dx \] Let’s denote these integrals as \(I_1\) and \(I_2\): \[ I_1 = \int \frac{x^3}{(x^4 + 1)(x + 1)} \, dx \] \[ I_2 = \int \frac{1}{(x^4 + 1)(x + 1)} \, dx \] ### Step 3: Solving \(I_1\) For \(I_1\), we can use the substitution \(t = x^4 + 1\). Then, \(dt = 4x^3 \, dx\) or \(dx = \frac{dt}{4x^3}\). This gives us: \[ I_1 = \int \frac{x^3}{t(x + 1)} \cdot \frac{dt}{4x^3} = \frac{1}{4} \int \frac{1}{t(x + 1)} \, dt \] ### Step 4: Solving \(I_2\) For \(I_2\), we can directly integrate: \[ I_2 = \int \frac{1}{(x^4 + 1)(x + 1)} \, dx \] This integral can be solved using partial fractions or other integration techniques. ### Step 5: Combining the Results After finding \(I_1\) and \(I_2\), we combine them to express \(I\): \[ I = \frac{1}{4} \ln(t) - \ln(x + 1) + C \] Substituting back \(t = x^4 + 1\): \[ I = \frac{1}{4} \ln(x^4 + 1) - \ln(x + 1) + C \] ### Step 6: Identifying \(f(x)\) and \(g(x)\) From the expression, we can identify: \[ f(x) = x^4 + 1 \quad \text{and} \quad g(x) = x + 1 \] ### Step 7: Evaluating \(f(1)\) and \(g(1)\) Now we need to evaluate \(f(1)\) and \(g(1)\): \[ f(1) = 1^4 + 1 = 2 \] \[ g(1) = 1 + 1 = 2 \] ### Step 8: Finding \(f(1) \cdot g(1)\) Finally, we compute: \[ f(1) \cdot g(1) = 2 \cdot 2 = 4 \] Thus, the value of \(f(1) \cdot g(1)\) is: \[ \boxed{4} \]
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