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The focal chord of the parabola y^(2)=32...

The focal chord of the parabola `y^(2)=32x` touches the ellipse `(x^(2))/(4^(2))+(y^(2))/(2^(2))=1` in the first quadrant at the point

A

`(2, sqrt3)`

B

`((sqrt3)/(2), (3)/(2))`

C

`((4)/(sqrt2),(2)/(sqrt2))`

D

`((2)/(sqrt2),(4)/(sqrt2))`

Text Solution

Verified by Experts

The correct Answer is:
A
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