How many mitotic division takes place for complete development of female gametophyte in an angiosperm ?

Options

A. 4
B. 3
C. 2
D. 1

Answer

To determine how many mitotic divisions take place for the complete development of the female gametophyte in an angiosperm, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding the Female Gametophyte Development**:
- In angiosperms, the female gametophyte develops from a megasporangium (ovule) which contains a megasporocyte (megaspore mother cell).

2. **Meiotic Division**:
- The megasporocyte undergoes one meiotic division to produce four haploid megaspores. However, typically only one of these megaspores survives to develop into the female gametophyte.

3. **Mitotic Divisions**:
- The surviving megaspore undergoes mitotic divisions.
- The first mitotic division of the megaspore results in two nuclei.
- The second mitotic division results in four nuclei.
- The third mitotic division results in eight nuclei.

4. **Formation of the Female Gametophyte**:
- After the three mitotic divisions, the eight nuclei are organized into the structure of the female gametophyte (embryo sac), which consists of one egg cell, two synergids, three antipodal cells, and one central cell with two polar nuclei.

5. **Conclusion**:
- Therefore, for the complete development of the female gametophyte in an angiosperm, a total of **three mitotic divisions** occur.

### Final Answer:
The number of mitotic divisions that take place for the complete development of the female gametophyte in an angiosperm is **3**.

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