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A plant with genotype AABbCcDD is self p...

A plant with genotype AABbCcDD is self polinated. Provided that the four genes are independently assorting, what proportion of the progeny will show the genotype AAbbccDD?

A

`1//4`

B

`1//16`

C

`1//64`

D

`1//256`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of determining the proportion of progeny with the genotype AABbccDD from a self-pollination of a plant with the genotype AABbCcDD, we can follow these steps: ### Step 1: Identify the Gametes The plant with genotype AABbCcDD can produce the following gametes based on the independent assortment of alleles: - From AAB: The only possible gamete is AB (since AA is homozygous). - From Bb: Possible gametes are B and b. - From Cc: Possible gametes are C and c. - From DD: The only possible gamete is D (since DD is homozygous). Thus, the possible gametes are: 1. ABCD 2. ABcD 3. AbCD 4. AbcD
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