How many different types of genetically different gametes will be produced by a heterozygous plant having the genotype AABb Ccdd ?

Options

A. Two
B. Four
C. Eight
D. Sixteen

Answer

To determine how many different types of genetically different gametes will be produced by a heterozygous plant with the genotype AABbCcdd, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotype**: The genotype given is AABbCcdd. We will analyze each gene separately to determine how many alleles are heterozygous.

2. **Identify Heterozygous Alleles**:
- For gene A: The genotype is AA, which is homozygous (only one type of allele).
- For gene B: The genotype is Bb, which is heterozygous (two types of alleles: B and b).
- For gene C: The genotype is Cc, which is also heterozygous (two types of alleles: C and c).
- For gene D: The genotype is dd, which is homozygous (only one type of allele).

3. **Count Heterozygous Genes**:
- There are 2 heterozygous genes (B and C) in the genotype.

4. **Use the Formula for Gamete Formation**: The number of different types of gametes can be calculated using the formula \(2^n\), where \(n\) is the number of heterozygous gene pairs.
- Here, \(n = 2\) (from genes B and C).

5. **Calculate the Number of Gametes**:
- Using the formula:
\[ 2^n = 2^2 = 4 \]
- Thus, the number of different types of genetically different gametes produced is 4.

### Final Answer:
The plant with the genotype AABbCcdd will produce **4** different types of genetically different gametes.

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