The minimum number of meiotic divisions to obtain 1000 pollen of wheat are

Options

A. 250
B. 500
C. 1000
D. 1250

Answer

To solve the problem of determining the minimum number of meiotic divisions required to obtain 1000 pollen grains of wheat, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Meiotic Division**:
- Meiotic division is a type of cell division that results in four daughter cells from one mother cell. Each of these daughter cells can develop into a pollen grain.

2. **Identifying the Number of Pollen Grains Needed**:
- We need to obtain 1000 pollen grains.

3. **Calculating the Number of Daughter Cells Produced**:
- Since one meiotic division produces four daughter cells, we can set up the relationship:
\[ \text{Number of daughter cells} = 4 \times \text{Number of meiotic divisions} \]

4. **Setting Up the Equation**:
- To find the number of meiotic divisions (let's denote it as \( x \)), we need:
\[ 4x = 1000 \]

5. **Solving for \( x \)**:
- Dividing both sides of the equation by 4 gives:
\[ x = \frac{1000}{4} = 250 \]

6. **Conclusion**:
- Therefore, the minimum number of meiotic divisions required to obtain 1000 pollen grains is **250**.

### Final Answer:
The minimum number of meiotic divisions to obtain 1000 pollen of wheat is **250**.

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