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Genes A and B are necessary for normal h...

Genes A and B are necessary for normal hearing. A deaf man marries a deaf woman and all their children have normal hearing. The genotype of the parents are

A

`ppqq xxppQq`

B

`ppqqxxPPqq`

C

`"ppQQ"xx"ppQq"`

D

`PPqqxx"ppQQ"`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the genotypes of the deaf parents given that all their children have normal hearing. We know that genes A (represented as P) and B (represented as Q) are necessary for normal hearing, and that both genes must be present in their dominant forms (capital P and capital Q) for the offspring to have normal hearing. ### Step-by-Step Solution: 1. **Understanding the Genes**: - For normal hearing, an individual must have at least one dominant allele for both genes A (P) and B (Q). - This means the genotypes that can express normal hearing are: - Capital P (dominant) and capital Q (dominant) - Possible combinations include: - Capital P, Capital Q (normal hearing) - Capital P, small q (normal hearing) - small p, Capital Q (normal hearing) 2. **Analyzing the Parents**: - Both parents are deaf, which means they must have the recessive genotype for both genes. Therefore, they cannot have any dominant alleles (capital P or capital Q). - The only possible genotype for both parents that would result in them being deaf is: - small p, small p (for gene A) - small q, small q (for gene B) 3. **Children's Hearing**: - The problem states that all children have normal hearing. This indicates that the parents must carry at least one dominant allele for each gene, despite being phenotypically deaf. - The only way this can happen is if both parents are heterozygous for one gene while being homozygous recessive for the other gene. 4. **Determining the Genotypes**: - The only combination that allows for normal hearing in the offspring while both parents are deaf is: - Parent 1: small p, small p, capital Q, small q (heterozygous for gene B) - Parent 2: small p, small p, capital Q, small q (heterozygous for gene B) - This means that each parent can contribute a capital Q to the offspring, allowing for normal hearing. 5. **Conclusion**: - The correct genotypes for the parents are: - Parent 1: small p, small p, capital Q, small q - Parent 2: small p, small p, capital Q, small q ### Final Answer: The genotype of the parents is: - Parent 1: small p, small p, capital Q, small q - Parent 2: small p, small p, capital Q, small q
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